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Gnoma [55]
3 years ago
15

The masses to the nearest kilogram of nine men were:

Mathematics
2 answers:
tigry1 [53]3 years ago
6 0
82kg is the answer I did research and I’m 90% sure that the answer
serious [3.7K]3 years ago
5 0

Answer:

82 kg

Step-by-step explanation:

To find the mean of a set of values, we must add them up and divide by the number of values.

Step 1, adding the values:

75+68+78+82+85+90+88+92+76=\\734

Step 2, dividing by the # of terms:

There are 9 terms in total.

\frac{734}{9} =\\81.556

To the nearest kilogram, we can round 81.556 into 82.

The mean mass of the 9 men was \fbox{82} kg.

<em>I hope this helps! Let me know if you have any questions :)</em>

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How do we convert decimal numbers into binary numbers 2483?.
alisha [4.7K]

Answer:

Places in binary coding

1 - 2 - 4 - 8 - 16 - 32 - 64 - 128 - 256 - 512 - 1024 - 2048

2483 - 2048 = 435      there is 1 in the 2048 position

435 - 256 = 179    there is 1 in the 256 position

179 - 128 = 51        there is 1 in the 128 position

51 - 32 = 19         there is 1 in the 32 position

19 - 16 = 3           there is 1 in the 16 position

3 - 2 = 1            there is 1 in the 2 position

1 - 1 = 0             there is 1 in the 1 position

10011011 0011     would be the binary result

Check:

2048 + 0 + 0 + 256 + 128 + 0 + 32 + 16 + 0 + 0 + 2 + 1 = 2483

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3 years ago
A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.​
Papessa [141]

<u>Answer:</u>

\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}

<u>Step-by-step explanation:</u>

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}

\bf \implies n_{cubes} = \dfrac{20cm \times  6cm \times 4cm .}{2cm  \times 2cm  \times 2cm } \\\\\bf\implies n_{cubes}  = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }

<h3><u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>

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3 years ago
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