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3 years ago

The masses to the nearest kilogram of nine men were:

Mathematics

2 answers:

tigry1 [53]3 years ago

6 0

82kg is the answer I did research and I’m 90% sure that the answer

serious [3.7K]3 years ago

5 0

Answer:

82 kg

Step-by-step explanation:

To find the mean of a set of values, we must add them up and divide by the number of values.

Step 1, adding the values:

$75+68+78+82+85+90+88+92+76=\\734$

Step 2, dividing by the # of terms:

There are 9 terms in total.

$\frac{734}{9} =\\81.556$

To the nearest kilogram, we can round 81.556 into 82.

The mean mass of the 9 men was $\fbox{82}$ kg.

<em>I hope this helps! Let me know if you have any questions :)</em>

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sasho [114]

Answer is 54^2.

since there are triangles in this one, it is easier to do this. all you have to do is make boxes in and since there are angles, outside the lines. like this picture.

the orange is 1
red and dotted is 2
blue is 3
purple is 4(a regular box which should be easy to count.

all you have to do is add up all the boxes within the boundaries.
boundary 1: 12
boundary 2: 18
boundary 3: 6
boundary 4: 36

now when the boundary has a triangle in it (1, 2, & 3) divide the number you got in half or 2.
boundary 1: 6
boundary 2: 9
boundary 3: 3

the ractangle box doesn't not get divided.
boundary 1: 6
boundary 2: 9
boundary 3: 3
boundary 4: 36

add all the numbers you got now for each boundary and that would be your area squared.

6+9+3+36=54^2

so your final answer is 54^2.

i hope this helps you.

3 0

3 years ago

The length around the outside of semicircle O from point L through point M to point N is 14 centimeters. The perimeter of semici

Luden [163]

The area would be 83.67 cm.

A semicircle is half of a circle. The perimeter of the semicircle would be half of the perimeter (circumference) of the entire circle. The formula for circumference is:

C=πd

Using our information, we have

22.92 = 0.5(3.14)d
22.92 = 1.57d

Divide both sides by 1.57:

22.92/1.57 = 1.57d/1.57
14.6≈d

Since the diameter is 14.6, the radius is 14.6/2 = 7.3.

We use the radius for the area of the semicircle:

A=0.5πr²
=0.5(3.14)(7.3)²
=83.67

3 0

3 years ago

Given h(x) = -X – 2, solve for x when h(x) = 3.

Naya [18.7K]

The answer should be h(3)= -5

6 0

3 years ago

Read 2 more answers

Which statement isbtrue about the end behavior of the graphed function

kicyunya [14]

<span> As the x-values go to negative infinity the functions values go to positive infinity</span>

8 0

3 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.

$h^-^1\ o\ h$

$\frac{(3x+4)-4}{3}\\\\=\frac{3x+4-4}{3}\\\\=\frac{3x}{3}\\\\=x$

Now substitute (-3) in place of (x),

$=-3$

8 0

3 years ago