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MakcuM [25]
2 years ago
12

Annie's soccer team is conducting a passing drill in which each of the 11 members of the soccer team must pass the ball to each

of the other members exactly three times. How many times must the ball be passed before the passing drill is over?
Mathematics
2 answers:
jeka942 years ago
8 0

Answer:

33

Step-by-step explanation:

if each of the 11 must pass it 3 times, you multiply. 11×3 is equal to 33.

oh shoot I cant figure out how to delete comments but someone told me this is wrong ;(

Paladinen [302]2 years ago
3 0

Answer: 330

Step-by-step explanation: 11 x 10 = 110. 3 x 110 = 330

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How many km are equal to 3,400 m
Archy [21]
1 km = 1000 m

So 

x km = 3,400 m

that means 3.4 km would be equal to 3,400 m

your final answer is

\boxed{\bf{3.4~km}}
3 0
2 years ago
(Solving Equations) Ken has $20.00. Coffee costs $4.79 per pound. Which equation will calculate the number of pounds of coffee,
aev [14]

Answer: A. 4.79(n)=20.00

Step-by-step explanation:

we need to find what amount of coffee (per pound) is equivalent to $20.00

so we take the unknown amount (n) and multiply it by $4.79

for example, say Ken wants 4 pounds, we need to know if it is equivalent to $20.00

so take 4.79 and multiply it by 4 to see if it is equal to or less than $20.00 in this case $4.79 x 4 = $19.16  

hope this helps (^_^)

6 0
2 years ago
Read 2 more answers
Y is a random variable that is distributed N(-16, 1.21). Find k such that Prob(-15.043 < Y ≤ k) = 0.1546. (Round your answer
IgorLugansk [536]

Transform <em>Y</em> to <em>Z</em>, which is distributed N(0, 1), using the formula

<em>Y</em> = <em>µ</em> + <em>σZ</em>

where <em>µ</em> = -16 and <em>σ</em> = 1.21.

Pr[-15.043 < <em>Y</em> ≤ <em>k</em>] = 0.1546

Pr[(-15.043 + 16)/1.21 < (<em>Y</em> + 16)/1.21 ≤ (<em>k</em> + 16)/1.21] = 0.1546

Pr[0.791 < <em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] - Pr[<em>Z</em> < 0.791] = 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] = 0.1546 + Pr[<em>Z</em> < 0.791]

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546 + 0.786

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.940

Take the inverse CDF of both sides (<em>Φ(x)</em> denotes the CDF itself):

(<em>k</em> + 16)/1.21 ≈ <em>Φ⁻¹</em> (0.940) ≈ 1.556

Solve for <em>k</em> :

<em>k</em> + 16 = 1.21 • 1.556

<em>k</em> ≈ -14.118

8 0
2 years ago
The surface area of a cylinder consists of the sum of the areas of what shapes?
Paraphin [41]
<span>The surface area of a cylinder includes the bases which are circles and the side which is a rectangle</span>
5 0
2 years ago
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Solve for x <br>3(x - 2) = 6x - 12<br>​
nalin [4]

Answer:

The answer is 2

Step-by-step explanation:

Here's how I got it:

3(x - 2) = 6x - 12

Multiply 3 times x and 3 times 2, this is what you would get

3x - 6 = 6x - 12

Then, subtract the lowest x with the bigger X, this way you would have x on one side:

3x - 6 = 6x - 12

-3x        -3x

This is what you should have after this:

-6 = 3x - 12

Now, to get the variable (letter that represents a number) by itself, you have to add 12 to both sides like this:

-6 = 3x - 12

+12        +12

You would get this:

6 = 3x

Finally, you have to get x by itself, so you have to divide 3 on both sides like this

6/3 = 3/3 x

That's why, your answer is 2

5 0
3 years ago
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