In order to graph a system of linear equations, I need my equations to be in what form?

If x is a negative number, what is always true about the solution to the problem -8 + x? explain

Fofino [41]

<h3>Answer:</h3>

$-8 +x$ will always be negative if $x$ is a negative number.

<h3>Explanation:</h3>

Because the sum of two negative numbers are always negative.

6 0

3 years ago

What is the area when radius=2.6in

fomenos

Answer:

Hope this helps!

Step-by-step explanation:

Area = π · r2 = 3.14 · 2.62 = 21.24 square inches.

7 0

3 years ago

Pls i need help is due soon

Dafna11 [192]

Answer:

step1

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Halp me: ´` ) please : ´` > i need halp please : ^ l

klio [65]

Answer:

Halp u

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If P and Q are two sets then n( P-Q) means ?

Lapatulllka [165]

$\huge{\mathbb{ \tt{ANSWER}}}$

I shall use the symbol U for union

^ for intersection

~ for complement

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

#CarryOnLearning

#LetsEnjoyTheSummer

8 0

3 years ago