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3 years ago

Solve (x+10)^5=70 plz i am desperate

Mathematics

2 answers:

muminat3 years ago

8 0

Answer:

Us.e Math.way for these type of questions

Step-by-step explanation:

kodGreya [7K]3 years ago

6 0

Answer:

The answer your calculator showed is correct.

Step-by-step explanation:

you would do x+10=fifth root of 70.... then just subtract 10. you are left with x=(fifth root of 70)-10

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Enter the mixed number as a decimal 3 and 1 over 10

12345 [234]

3.1 i think but hopefully that might help

4 0

3 years ago

Tell whether the relation is a function.

pshichka [43]

Answer:

Step-by-step explanation:

The easiest way to tell if a relation is a function is to look at the x coordinates. If none of them are the same in the set, then the relation is a function. If any of the x values are used more than once in the set, it is only a relation. This set uses -3 two times, so it is a relation.

8 0

4 years ago

Read 2 more answers

If the x and y values in each pair of a set of ordered pairs are interchanged the resulting set of ordered pairs is known as the

pochemuha

Answer:

Inverse of a relation

Reasoning:

the inverse of a function is a full function, this is just a set of pairs. A set of pairs, or relation, where x and y values interchange are inverse of the relation. A one to one function is when a function's inverse is also a function (doesn't have more than one y for each x) which can be tested for on the normal function's graph with a HORIZONTAL line test. A normal parabola isn't one to one. An onto function has to do with every value being used (I don't remember much about them, but once again this isn't a function, but rather a specific set of pairs/data)

Example of inverse of a relation:

Relation: {(0,5), (3,2)}

Inverse: {(5,0), (2,3)}

Example of inverse of a function:

f(x)=5x

f-1(x)=x/5

Example of a one to one function:

f(x)=x+1

4 0

3 years ago

Axis of symmetry: x=4; points: (3,-2), (6,-26); opening downward

Andru [333]

Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k

we have some points
(3,-2) and (6,-26)
input and solve for a and k

(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k

(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k

we have

-2=a+k
-26=4a+k
multiply first equation by -1 and add to second

2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k

-24=3a
divide both sides by 3
-8=a

-2=a+k
-2=-8+k
add 8 to both sides
6=k

the equation is
$y=-8(x-4)^2+6$

3 0

3 years ago

Given the Function:

sergey [27]

F(x)=-2e^x
x=3
f(3)=-2e^3
pemdas so exponents first
e^3
e=2.718281828454590
cube that
20.0855

now we have
-2 times 20.0855=-40.1711

answer should be -40.1711
(I see what you did wrong, if -6=-2 times e^3, divide -2, 3=e^3, maybe you just put -2 times 3 by mistake)

5 0

4 years ago

Read 2 more answers