Molarity= moles of solute / liters of solution
2moles/0.75 L= ???? M
Answer:
a) fraction of carbon−14 in a piece of charcoal remains after 14.0 years.
b) fraction of carbon−14 in a piece of charcoal remains after
c) fraction of carbon−14 in a piece of charcoal remains after .
Explanation:
The fraction of a radioactive isotope remaining at time t is given by:
Taking log both sides:
[A] = fraction at given time t
= half life of the carbon−14 =5,730 years
a)When , t = 14 years
b)When , t =
c)When , t =
It is B, and also for a moment I didn't understand that 4.69 x 10^22. I almost did this whole problem wrong.
I would go with D because it contains lots of materials just like composite materials do