Answer
Explanation:O2 = 1.7×10-3M;
N2 = 6.4×10-3M;
NO = 1.1 10-5M.
The name is Copper(II) Oxide and/or Cupric Oxide.
Cu is Copper and O is Oxygen.
Usually when the Oxygen ion is placed after another, it's name is Oxide.
I believe the correct answer is the first option. To increase the molar concentration of the product N2O4, you should increase the pressure of the system. You cannot determine the effect of changing the temperature since we cannot tell whether it is an endothermic or an exothermic reaction. Also, decreasing the number of NO2 would not increase the product rather it would shift the equilibrium to the left forming more reactants. The only parameter we can change would be the pressure. And, since NO2 takes up more space than the product increasing the pressure would allow the reactant to collide more forming the product.
Answer:
Required number is the vertical coordinate of the intersection point of a line at 60°C with the graph of the KNO₃.
