2x-3y = 13
x + 2y = -4
For this case, the first thing we can do is rewrite the system of equations as:
2x-3y = 13
-2x-4y = 8
We now add both equations obtaining:
-7y = 21
We clear y:
y = 21 / -7
y = -3
We substitute the valos of y = -3 in any of the equations to find x:
x + 2 (-3) = - 4
We clear x:
x-6 = -4
x = -4 + 6
x = 2
Answer:
2x-3y = 13
x + 2y = -4
The solution to the system of equations is:
x = 2
y = -3
Answer:
Step-by-step explanation:
Given the expression (((x^3)^2))^2
a) Differentiating the function with respect to x using chain rule.
Given y = (((x^3)^2))^2
Let u = (x³)²
y = u²; dy/du = 2u
Let p = x³; dp/dx = 3x²
u = p²; du/dp = 2p
Applying the chain rule formula:
dy/dx = dy/du • du/dp • dp/dx
substitute in the formula
dy/dx = 2u•2p•3x²
Since u = (x³)² and p = x³
dy/dx = 2(x³)²(2x³)(3x²)
dy/dx = 12x^6•x^5
dy/dx = 12x¹¹
b) Using property of exponent
y = (((x^3)^2))^2
y = (x^6)²
y = x¹²
dy/dx = 12x^12-1
dy/dx = 12x^11
The answer is (-4,-2) .
You substitute the value of Y
solve the equation then substitute
the value of X, then again Slove