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Vinil7 [7]
3 years ago
13

Help Help HELP PLZ ASAP!!!!! No trolling I Really need help.

Mathematics
1 answer:
ankoles [38]3 years ago
4 0

Answer:

Step-by-step explanation:

9: y=5(x-1)^2-3

standard form: y=5x^2-10x+2

10: y=3(x+3)^2+2

standard form: y=3x^2+18x+29

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g100num [7]

Answer: mean- 38

median- 37

mode- no mode

range- 30

Step-by-step explanation:

5 0
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Equal to a+b on the algebra
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Greeley [361]

Answer:

B

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see attachment

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FIND THE UNIT RATE AND ROUND TO THE NEAREST HUNDREDTHS IF NECESSARY. Jasigreen's class opened last year and serviced 6,840 custo
Vladimir [108]
<span>6840 customers ... 45 days<span>
x customers = ? ... 1 day

If you would like to know how many customers were in Jasigreen's class in 1 day, you can calculate this using the following steps:

6840 * 1 = 45 * x
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4 0
3 years ago
The initial price of buzz stock is $20 per share. After 20 days the stock price is $30 per share and after 40 days the price is
Temka [501]

Answer:

s(t) = -\dfrac{t^2}{160}+\dfrac{5}{8}t+20

Step-by-step explanation:

given,

initial price of buzz stock = $ 20 per share

after 20 days

stock price = $30 per share

after 40 days

the price =  $35 per share

let say it is modeled by

y = ax² + b x + c

x = number of days

y = stock price

x = 0 y = 20

20 = a x 0 + b x 0 + c

c = 20

x = 20 y = 30

30 = 20² a + 20 b + 20

400 a + 20 b = 10...........(1)

x = 40 y = 35

35 = 40² a + 40 b + 20

1600 a + 40 b = 15...........(2)

solving equation (1)and (2)

a = - 1/160

b = 5/8

y = -\dfrac{x^2}{160}+\dfrac{5}{8}x+20

s(t) = -\dfrac{t^2}{160}+\dfrac{5}{8}t+20

hence , the above equation is multipart function

5 0
3 years ago
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