1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
padilas [110]
3 years ago
9

Explain why decomposition uses solar energy

Chemistry
1 answer:
koban [17]3 years ago
4 0

Answer:

Without the sun's energy, biological life would not be able to exist to decompose. Many microbes and fungi do their best work out of direct sunlight.

You might be interested in
An experiment shows that a 236 mL gas sample has a mass of 0.443 g at a pressure of 740 mmHg and a temperature of 22 ∘C. What is
aleksley [76]

Answer:

49.2 g/mol

Explanation:

Let's first take account of what we have and convert them into the correct units.

Volume= 236 mL x (\frac{1 L}{1000 mL}) = .236 L

Pressure= 740 mm Hg x (\frac{1 atm}{760 mm Hg})= 0.97 atm

Temperature= 22C + 273= 295 K

mass= 0.443 g

Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be

n=\frac{PV}{RT}, where R (constant)= 0.082 L atm mol-1 K-1

Let's plug in what we know.

n=\frac{(0.97 atm)(0.236 L)}{(0.082)(295K)}

n= 0.009 mol

Let's look back at MM= \frac{m}{n} and plug in what we know.

MM= \frac{0.443 g}{0.009 mol}

MM= 49.2 g/mol

3 0
3 years ago
What is the lewis dot structure of NaBr
Anon25 [30]
<span><span>LiF, LiCl, LiBr, LiI, LiAtNaF, NaCl, NaBr, NaI, NaAtKF, KCl, KBr, KI, KAt</span><span>RbF, RbCl, RbBr, RbI, RbAt CsF, CsCl, CsBr, CsI, CsAt FrF, FrCl, FrBr, FrI, FrAt<span>
</span></span></span>
3 0
3 years ago
This type of pollution will decay naturally
butalik [34]
Withdrawal is the answer to your question.
3 0
3 years ago
The molar heat capacity of an unknown substance is 92.1 J/mol-K. If the unknown has a molar mass of 118 g/mol, what is the speci
dlinn [17]

Answer : The specific heat (J/g-K) of this substance is, 0.780 J/g.K

Explanation :

Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.

1 mole of substance releases heat = 92.1 J/K

As we are given, molar mass of unknown substance is, 118 g/mol that means, the mass of 1 mole of substance is, 118 g.

As, 118 g of substance releases heat = 92.1 J/K

So, 1 g of substance releases heat = \frac{92.1}{118}=0.780J/g.K

Thus, the specific heat (J/g-K) of this substance is, 0.780 J/g.K

8 0
3 years ago
Neutralization Reactions
marta [7]

Answer:

2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O

Explanation:

2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O

H+

O2-

OH-

Ba2+

Ca2+

NO3-

P 5+, 3+, 3-

H2O

4 0
3 years ago
Other questions:
  • Antibiotic-resistant bacteria have an enzyme, penicillinase, that catalyzes the decomposition of the antibiotic. The molecular m
    13·1 answer
  • In a ceiling fan, N, electrical energy is converted to M, Kinetic energy. Some of the energy is "wasted" as heat. What is someth
    11·2 answers
  • Why do substances with weak intermolecular forces form solids at low melting points?
    14·1 answer
  • What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M p
    7·1 answer
  • What geologic features might form in convergent boundaries<br>Pls help
    7·1 answer
  • How can carbon dating be used to study the history of the earth?
    6·1 answer
  • Of the following transitions in the Bohr hydrogen atom, which of the following
    10·1 answer
  • apparently 90% of people marry there 7th grade love. since u have read this, u will be told good news tonight. if u don't pass t
    12·2 answers
  • PLEASE HELP. WILL GIVE BRAINLIEST AND QUESTION WORTH A 100 POINTS. NEED ANDWER ASAP!
    5·1 answer
  • Please help as soon as possible!!!
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!