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2 years ago

Why did most of the alpha particles go straight through the gold foil in Rutherford's experiment?

Chemistry

1 answer:

andre [41]2 years ago

4 0

Answer:

The fact that most alpha particles went straight through the foil is because the atom is mostly empty space.

Those that passed straight through did so because they didn't encounter any nuclei.

Explanation:

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The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

3 years ago

in a certain solvent is first order with respect to (CH3)3CBr and zero order with respect to OH2. In several experiments the rat

Inga [223]

Answer:

Ea= -175.45J

A= 3.5×10^14

k=3.64 ×10^14 s^2.

Explanation:

From

ln k= -(Ea/R) (1/T) + ln A

This is similar to the equation of a straight line:

y= mx + c

Where m= -(Ea/R)

c= ln A

y= ln k

Therefore

21.10 3 104= -(Ea/8.314)

Ea=-( 21.10 3 104×8.314)

Ea= -175.45J

b) ln A= 33.5

A= e^33.5

A= 3.5×10^14

k= Ae^-Ea/RT

k= 3.5×10^14 × e^ -(-175.45/8.314×531)

k = 3.64 ×10^14 s^2.

8 0

3 years ago

One of the products of photosynthesis is<br> carbon dioxide.<br> fire.<br> oxygen gas.<br> mass.

kondor19780726 [428]

One of the products of photosynthesis is carbon dioxide

5 0

3 years ago

Carbon is the main constituent of hydrocarbons. Why some are called unsaturated hydrocarbon? Briefly describe.

maw [93]

Some hydrocarbons are regarded as unsaturated because they contain double or triple bonds between adjacent carbon atoms.

<h3>What are hydrocarbons?</h3>

Hydrocarbons are any organic compounds that contain hydrogen and carbon in its structure.

Hydrocarbons can be grouped into the following based on whether they contain single or double bonds:

Saturated hydrocarbons - contain only single bonds e.g. alkanes
Unsaturated hydrocarbons - contain double and triple bonds e.g. alkenes

Therefore, it can be said that some hydrocarbons are regarded as unsaturated because they contain double or triple bonds between adjacent carbon atoms.

Learn more about hydrocarbons at: brainly.com/question/17578846

5 0

1 year ago

Help now im not trying to fail

Alekssandra [29.7K]

Answer:

i cant see the whats in the picture

5 0

2 years ago

Read 2 more answers