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tamaranim1 [39]
3 years ago
10

PLEASE HELP!!!

Chemistry
1 answer:
kakasveta [241]3 years ago
8 0

Answer:

dfgdhfjkl;jhgfdsAZXcvdfcgbwegbfgvdavsbhgsvadrfgvrdt

Explanation:

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) In a nuclear reaction, which quantity is the same before and after the change? (1 point)
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Answer:

In alpha decay, shown in Fig. 3-3, the nucleus emits a 4He nucleus, an alpha particle. Alpha decay occurs most often in massive nuclei that have too large a proton to neutron ratio. An alpha particle, with its two protons and two neutrons, is a very stable configuration of particles. Alpha radiation reduces the ratio of protons to neutrons in the parent nucleus, bringing it to a more stable configuration. Many nuclei more massive than lead decay by this method.

Explanation:

8 0
3 years ago
buffer consists of 0.50 M NaH2PO4 and 0.40 M Na2HPO4. Phosphoric acid is a triprotic acid (K a 1 = 7.2 × 10 − 3, K a 2 = 6.3 × 1
Levart [38]

Answer:

The Ka value used for the buffer system is :- Ka2 = 6.3\times 10^{-8} pKa2 = 7.2

pH = 7.1

Explanation:

The buffer system given in the question is :-

NaH_2PO_4 and Na_2HPO_4

The reaction taking place is:-

H_2PO_4^-\rightleftharpoons HPO_4^{2-}

The Ka value used for the buffer system is :- Ka2 = 6.3\times 10^{-8} pKa2 = 7.2

The pH can be calculated as:-

pH=pKa+\log\frac{Na_2HPO_4}{NaH_2PO_4}

pH = 7.2 + log 0.40/0.50 = 7.1

7 0
4 years ago
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