All categories

2 years ago

What is a percent volume of ethanol c2h60 in the final solution when 85 ml of it is diluted to a volume?

Chemistry

1 answer:

Ilya [14]2 years ago

3 0

34% I believe

Hope this helps!
STSN

You might be interested in

How co you find anhydrides?

svet-max [94.6K]

<span>took two ethanoic acid molecules and removed a molecule of water between them you would get the acid anhydride, ethanoic anhydride. The old name: acetic anhydride.</span>

3 0

3 years ago

What are 2 chemical changes of water?

zmey [24]

Hydrogen peroxide in water and adding kool- aid powder to water so the liquid turns red

3 0

2 years ago

Find the molecular mass of MgSO4

rewona [7]

120.38 g/mol is the answer

7 0

3 years ago

Read 2 more answers

Identify one natural process that may cause sudden climate changes.

Vesnalui [34]

Answer:

Global Warming , Volcanic Eruption

3 0

2 years ago

Show

SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}$ .....(1)

Molarity of $HCl$ solution = 0.75 M

Volume of $HCl$ solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

$\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles$

$CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)$

According to stoichiometry :

2 moles of $HCl$ require = 1 mole of $CaCO_3$

Thus 0.01875 moles of $HCl$ will require= $\frac{1}{2}\times 0.01875=0.009375moles$ of $CaCO_3$

Mass of $CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g$

Thus 0.9375 g of $CaCO_3$ is required to react with 25.0 ml of 0.75 M HCl

6 0

2 years ago