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joja [24]
3 years ago
13

Last month there was 4 sunny days for every raining day

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0

Answer:

ok

Step-by-step explanation:

You might be interested in
Solve b 4b+5=1+5b what is b
Leto [7]

Answer: b=4


Step-by-step explanation: Let's solve your equation step-by-step.

4b+5=1+5b

Step 1: Simplify both sides of the equation.

4b+5=5b+1

Step 2: Subtract 5b from both sides.

4b+5−5b=5b+1−5b

−b+5=1

Step 3: Subtract 5 from both sides.

−b+5−5=1−5

−b=−4

Step 4: Divide both sides by -1.

−b

−1

=

−4

−1

b=4


4 0
3 years ago
Read 2 more answers
Workers have packed 1,400 glasses in 7 boxes. If they pack 3 more boxes, how many glasses will they have packed in all?
11111nata11111 [884]

1box = 1400/7 = 200

200×3=600

1400+600=2000

8 0
3 years ago
Read 2 more answers
A local village recently reported that enrollment increase by 10 percent of last year if enrollment last year was 17,113 about h
yulyashka [42]
17113 divided by 100=171.13

171.13*10=1711.3

17113+1711.3=18824.3

You can then round this to get a whole number if you need to.

Hope I helped xx
8 0
3 years ago
1/2expand the equation 1/2(3+4t-10)=
Ivanshal [37]

\frac{1}{2} (3 + 4t - 10)

\frac{3}{2}  +  \frac{4t}{2}  -  \frac{10}{2}

(\frac{3}{2}  -  \frac{10}{2})  + 2t

\frac{ - 7}{2}  + 2t

- 3.5 + 2t

8 0
3 years ago
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 ce
julsineya [31]

Answer:

The proportion of students whose height are lower than Darnell's height is 71.57%

Step-by-step explanation:

The complete question is:

A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.

What proportion of proportion of students height are lower than Darnell's height.

Answer:

We first calculate the z-score corresponding to Darnell's height using:

Z=\frac{X-\mu}{\sigma}

We substitute x=161.4 , \mu=150, and \sigma=20 to get:

Z=\frac{161.4-150}{20} \\Z=0.57

From the normal distribution table, we read 0.5 under 7.

The corresponding area is 0.7157

Therefore the proportion of students whose height are lower than Darnell's height is 71.57%

8 0
3 years ago
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