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irina1246 [14]
3 years ago
12

HELPPPP: From the top of a light house 50 meters high, the angle of depression of a boat out at sea has a measure of 15°. Find t

o the nearest meter the distance from the boat to the foot of the light house, which is at sea level.

Mathematics
1 answer:
astraxan [27]3 years ago
5 0

Answer:

13m

Step-by-step explanation:

d=50tan(15)=13m

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find the slope and y intercept for the following equation by writing it in the form y=mx+b -8x+y=5 someone help please
vichka [17]

Answer:

slope = 8, y- intercept = 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Given

- 8x + y = 5 ( add 8x to both sides )

y = 8x + 5 ← in slope- intercept form

with slope m = 8 and y- intercept c = 5

8 0
3 years ago
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4×(x+1)−5=11 NEED HELPPPP
AleksandrR [38]
X=4 this is because 4 times (x+1)-5=11 the 1x then just turns to x because you can’t have a 1 next to x when it’s just one x.
4*(x+1)-5=11
4(x)-5=11
4x-5=11
+5=11
—————
4x=16
4. 4
———-
X=4
4 0
3 years ago
What’s the answer did anyone figure it out ?
olya-2409 [2.1K]

Answer:

NAswer to what

Step-by-step explanation:

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3 years ago
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Question 9
10 pts
An equilateral triangle with side length 1.5 is dilated with a scale factor of 4. What is the length of one
side of the image of the triangle?
A 0.375
B 3
C 1.5
D 6
6 0
3 years ago
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Which is the equation of a hyperbola with directrices at y = ±2 and foci at (0, 4) and (0, −4)?
Advocard [28]

Answer:

Step-by-step explanation:

First off, I'm assuming that when you said "directrices" you mean the oblique asymptotes, since hyperbolas do not have directrices they have oblique asymptotes.

If we plot the asymptotes and the foci, we see that where the asymptotes cross is at the origin. This means that the center of the hyperbola is (0, 0), which is important to know.

After we plot the foci, we see that they are one the y-axis, which is a vertical axis, which means that the hyperbola opens up and down instead of sideways. Knowing those 2 characteristics, we can determine that the equation we are trying to fill in has the standard form

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1

We know h and k from the center, now we need to find a and b. Those values can be found from the asymptotes. The asymptotes have the standard form

y = ±\frac{a}{b}(x-h)+k

Filling in our asymptotes as they were given to us:

y = ±\frac{2}{1}(x-0)+0 where a is 2 and b is 1. Now we can write the formula for the hyperbola!:

\frac{(y-0)^2}{4}-\frac{(x-0)^2}{1}=1 which of course simplifies to

\frac{y^2}{4}-\frac{x^2}{1}=1

4 0
4 years ago
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