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WARRIOR [948]
3 years ago
13

Solve and type in a different form by using the given theorems of logarithms. log N^3

Mathematics
2 answers:
Kipish [7]3 years ago
8 0
<h3><u>Answer:</u></h3>

Hence, the different form of log N^3 by using the given theorems of logarithms is:

\log N^3=3\log N

<h3><u>Step-by-step explanation:</u></h3>

We have to represent the given logarithmic function in some other form using the property of logarithm.

We are given a logarithmic function as:

\log N^3

As we know the property of logarithm that:

\log m^n=n\log m

Hence, we can represent our given function as:

\log N^3=3\log N

Hence, the different form of log N^3 by using the given theorems of logarithms is:

\log N^3=3\log N

timofeeve [1]3 years ago
5 0
Log N^3  = 3 log N

using the theorem log a^2  = 2 log a
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8y 2 + 17y + 2<br> What’s the answer for this question
Novosadov [1.4K]
So you first need to calculate 8y 2 which is basically 8x2 which equals 16 then add 16y + 17y which is 33 so your answer is 33y+2
3 0
3 years ago
The graph represents function 1, and the equation represents function 2:
kvv77 [185]

Answer:

Please check the explanation.

Step-by-step explanation:

We know that the slope or rate of change of the function can be:

  • positive
  • negative
  • zero, or
  • undefined

Function 1

From the function 1 graph, it is clear that the graph is a horizontal line. We must note that the horizontal line has a slope or rate of change zero. The reason is that the horizontal line can not rise vertically. i.e. y₂-y₁=0

so using the slope formula

Rate of change = m = y₂-y₁ / x₂-x₁

Taking two points (x₁, y₁) = (0, 4), (x₂, x₁) = (1, 4)

Rate of change = m = 4-4 / 1-0

Rate of change = m = 0/1

Rate of change = m = 0

Thus, the rate of change of function 1 is zero.

Function 2

We know the slope-intercept form of linear equation is

y = mx+b

where m is the rate of change or slope of the function and b is the y-intercept

Given the function

y = 8x+12

comparing with the slope-intercept form i.e. y = mx+b

Therefore, the rate of change of function 2 = m = 8

Conclusion

The rate of change of function 1  = 0

The rate of change of function 2  = 8

as

  • 8 - 0 = 8

Therefore, function 2 has 8 more rate of change of function than the rate of change of function 1.

6 0
3 years ago
Help please if it’s wrong is okay ig no links
Mkey [24]
1 2 3 4 & 5 would be the answers!
6 0
3 years ago
Solve for x!! helppppp
goldenfox [79]

Answer:

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Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Find the value of N please!!
V125BC [204]

Answer:

n = - 5

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} ⇔ a^{(m+n)}

\frac{a^{m} }{a^{n} } ⇔ a^{(m-n)}

Consider the left side

\frac{y^4.y^{n} }{y^2}

= \frac{y^{4+n} }{y^2}

= y^{4+n-2}

= y^{2+n}, then

y^{2+n} = y^{-3}

Since the bases on both sides are the same, equate the exponents

2 + n = - 3 ( subtract 2 from both sides )

n = - 5

6 0
3 years ago
Read 2 more answers
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