Answer:
He is percieved in a warm climate.
Explanation:
The frog doesn't feel too cold or too hot. He is just right.
Answer:
7.23 J
Explanation:
Step 1: Given data
- Mass of graphite (m): 566.0 mg
- Initial temperature: 5.2 °C
- Final temperature: 23.2 °C
- Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹
Step 2: Calculate the energy required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)
Q = 7.23 J
Answer:
The answer to your question is 24.32 g
Explanation:
Data
Atomic weight = ?
HCl volume = 125 ml
Molarity = 0.2
mass of metal = 0.304 g
Balanced chemical equation
M + 2HCl ⇒ MCl₂ + H₂
Process
1.- Calculate the moles of HCl
Molarity = moles / volume (L)
- Solve for moles
moles = Molarity x volume
moles = 0.2 x 0.125
= 0.025
2.- Calculate the moles of the Metal
1 mol of M ----------------- 2 moles of HCl
x ----------------- 0.025 moles of HCl
x = (0.025 x 1) / 2
x = 0.0125 moles of HCl
3.- Calculate the atomic weight of the metal
atomic weight ---------------- 1 mol
0.304 g ---------------0.0125 moles
Atomic weight = (1 x 0.304) / 0.0125
Atomic weight = 24.32 g
Answer:
POSITIVE DESCRIBES AN INCREASE IN SPEED AND NEGATIVE DESCRIBES A DECREASE IN SPEED.
Explanation:
