Answer:
Br2(l) → BrO3-(aq) + Br-(aq)
A) Br2 = 3, OH - = 6
B) Br2 = 3, OH - = 3
C) Br2 = 2, OH - = 5
D) Br2 = 1, OH - = 2
E) Br2 = 1, OH - = 6
True:
They are Nobel gassed! They are un-reactive because there outer shell (valence) is completely full. This means they do not want to lose or gain on electron so they do not react.
We can use the ideal gas law equation to find the number of moles in the gas
PV = nRTwhere P - pressure - 1.2 atm x 101 325 Pa/atm = 121 590 Pa
V - volume - 3.94 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 15 °C + 273 = 288 K
substituting the values in the equation
121 590 Pa x 3.94 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 288 K
n = 0.200 mol
molar mass of gas is = mass / number of moles
molar mass = 12.8 g / 0.200 mol = 64 g/mol
molar mass of gas is 64 g/mol
The type of compound is formed between coach and a carboxylic acid alcohol + carboxylic acid → ester + water.
How carboxylic acids are formed?
A acid is produced after the acidic hydrolysis of esters and carboxylates are produced after the basic hydrolysis of an ester.
What are the functional group of alcohol and carboxylic acid?
Alcohols contain the hydroxyl functional group and may be primary, secondary, or tertiary. Ethers are compounds with an oxygen atom bonded to 2 alkyl groups. Aldehydes and ketones contain the carbonyl functional group
Can a compound be a acid and an alcohol?
Esters are represented by the formula RCOOR', where R and R' are hydrocarbon groups. The ester, which is compound derived from a carboxylic acid and an alcohol in which the OH of the acid is replaced by an OR group, looks somewhat sort of a n ether and also somewhat like a carboxylic acid.
Learn more about carboxylic acid :
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Both indicate the temperature at which the solid and liquid states of a substance are in equilibrium would be your answer.
This is beacause the melting point of a substance is the same as the freezing point of a substance. At this particular temp, the substance can be either a solid or a liquid.
hope this helps!
