Which equation represents the line that is perpendicular to the graph
1 answer:
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Answer:
see below
Step-by-step explanation:
The point-slope form of the equation of a line is ...
y -h = m(x -k)
for a line with slope m through point (h, k).
Comparing this to the given equation, you see that ...
h = -2, m = 1, k = -4
The line has a slope of 1 and goes through the point (-4, -2). This information is useful for graphing.
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You can also rearrange the equation to slope-intercept form by subtracting 2 from both sides.
y = x +2
This has a slope of 1 and crosses the y-axis at y=2. It graphs the same as the above.
Answer: some parts of your question is missing below is the missing data
Determine if the given vector field F is conservative or not. F = −6e^y, (−6x + 3z + 9)e^y, 3e^y
answer:
F is conservative
F = -6xe^y + ( 33 + 9 ) e^y + C
Step-by-step explanation:
The Potential functions for F so that F = ∇f.
F = -6xe^y + ( 33 + 9 ) e^y + C
attached below is a detailed solution
