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dybincka [34]
2 years ago
12

Which equation represents the line that is perpendicular to the graph

Mathematics
1 answer:
ella [17]2 years ago
7 0

Answer:

Here look at this graph this is your answer.

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PLZ HELP ME <br> I appreciate any help, especially if you can show me how you got the answer
Arte-miy333 [17]

Answer:

C

Step-by-step explanation:

Since this is an indererminate form, use L'Hopital

d(sint)/dt = cos(t)

d[ln(2e^t) - 1] = (2e^t)/[2e^t - 1]

As t --> 0,

cos(0) = 1

(2e^t)/[2e^t - 1] = 2

1/2 is the limit

5 0
3 years ago
Integrate the following. ∫<img src="https://tex.z-dn.net/?f=5x%5E%7B4%7D%20dx" id="TexFormula1" title="5x^{4} dx" alt="5x^{4} dx
Vadim26 [7]

Answer:

\displaystyle D)  {x}^{5}  +  \rm C

Step-by-step explanation:

we would like to integrate the following Integral:

\displaystyle \int 5 {x}^{4} \, dx

well, to get the constant we can consider the following Integration rule:

\displaystyle \int c{x} ^{n}  \, dx  =  c\int  {x}^{n}  \, dx

therefore,

\displaystyle 5\int  {x}^{4} \, dx

recall exponent integration rule:

\displaystyle \int {x} ^{n}  \, dx  =  \frac{ {x}^{n + 1} }{n + 1}

so let,

  • n = 4

Thus integrate:

\displaystyle  =  5\left( \frac{ {x}^{4+ 1} }{4 +  1}  \right)

simplify addition:

\displaystyle  =  5\left( \frac{ {x}^{5} }{5}  \right)

reduce fraction:

\displaystyle  =  {x}^{5}

finally we of course have to add the constant of integration:

\displaystyle  \boxed{ {x}^{5}  +  \rm C}

hence,

our answer is D)

7 0
3 years ago
Read 2 more answers
64 times -7/8 minus 1/2
Vesna [10]
64 \times (- \dfrac{7}{8}) -  \dfrac{1}{2}

=-56 -  \dfrac{1}{2}

=-56\dfrac{1}{2}
3 0
3 years ago
PLEASE HELP I DONT KNOw all THE DEFINITIONS TO THESE- MARK BRAINLIEST TOO
frozen [14]

Answer:

Factor

−

1

out of

−

3

x

2

+

4

x

−

7

.

−

(

3

x

2

−

4

x

+

7

)

Step-by-step explanation:

4 0
3 years ago
Please help the question is in the picture
olasank [31]

Answer:

Step-by-step explanation:

f(2x-3)

-(2x - 3) + 5

-2x + 3 + 5= -2x + 8

answer is A

4 0
3 years ago
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