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spayn [35]
3 years ago
15

Could anyone help me with this question?

Physics
2 answers:
Nana76 [90]3 years ago
3 0

The last 2. They both are correct. I hope this helps.

Olenka [21]3 years ago
3 0

The first three statements are true.

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Course hero N4M.6 A board has one end wedged under a rock having a mass of 380 kg and is supported by another rock that touches
aleksandrvk [35]

Answer:

Therefore it is save to carry a 62kg adult

Explanation:

From the question we are told that:

Mass m=380kg

Height of supporting Rock X=85cm

Length of BoardL_r=4.5m

Mass of board M_b=22kg

Mass of adult M_a=62  

Generally the moment of balance about wedge part about  is mathematically given by

N -Q + R = Mg + mg

0.85*N - Mg*2.25 - mg*(2.25 + x) = 0

0.85*N  = + Mg*2.25 + mg*(2.25 + x)

where

N+R=4547

therefore

N = 570.70588 + 1608.3529 + 714.823 x

if N=0 at fallen person

x=3.04m

Therefore it is save to carry a 62kg adult

8 0
3 years ago
A car generates 2,552 N and weighs 2,250 pounds. what is the rate of acceleration
Lilit [14]
Ans: a = 2.50 m/s^2

Explanation:
First convert the mass in its standard unit i.e. kilogram(kg):
2250 lbs = 1020.583kg

Next use Newton's Second law:
F = ma

Where F = 2552N
m = 1020.583kg

=> a = (2552/1020.583)
a = 2.50 m/s^2
6 0
3 years ago
A 2200 kilogram car is accelerating at 3.4 m/s/s. what is the NET force?
sdas [7]
We Know, F = m*a
F = 2200 * 3.4
F = 7480 Kg m/s²

So, your final answer is 7480
7 0
3 years ago
1. The current in a wire is 0.72A. Calculate the charge that passes through the wire in; a. 4 s b. 60 s c. 180 s d. 7 s e. 0.5 s
Vlad [161]
Let current be I, charge be Q and time be t.
Here we are provided with,
I = 0.72A
t = 4s / 60s / 180s / 7s / 0.5s
We know,
I = Q/t

Case I
---------
When, t = 4s
0.72 = Q/4
Q = 0.72 * 4 = 2.88C

Case II
----------
When, t = 60s
0.72 = Q/60
Q = 0.72 * 60 = 43.2C

Case III
-----------
When, t = 180s
0.72 = Q/180
Q = 0.72 * 180 = 129.6C

Case IV
-----------
When, t = 7s
0.72 = Q/7
Q = 0.72 * 7 = 5.04C

Case V
----------
When, t = 0.5s
0.72 = Q/0.5
Q = 0.72 * 0.5 = 0.36C
6 0
3 years ago
Three identical resistors have an equivalent resistance 15.6 ohm when they are connected in series. What is the resistance for e
attashe74 [19]

Answer:

R=5.2\ \Omega

Explanation:

In series combination, the equivalent resistance is given by :

R_{eq}=R_1+R_2+R_3+...

Let the identical resistors be R. We have, R_{eq}=15.6\ \Omega

So,

R+R+R=15.6\\\\3R=15.6\\\\R=\dfrac{15.6}{3}\\\\R=5.2\ \Omega

So, the resistance of each resistor is 5.2\ \Omega.

4 0
3 years ago
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