Let the given complex number
z = x + ix = 
We have to find the standard form of complex number.
Solution:
∴ x + iy =
Rationalising numerator part of complex number, we get
x + iy = 
⇒ x + iy = 
Using the algebraic identity:
(a + b)(a - b) = 
- 
⇒ x + iy = 
⇒ x + iy = 
[ ∵ 
]
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 1 - i
Thus, the given complex number in standard form as "1 - i".
Answer:
The equation is y=4/3x+4
Step-by-step explanation:
Answer:
Step-by-step explanation:
First, you have to substitute both functions into the equation to get:
Then, you distribute the negative sign in front of g(x) to get:
And finally, you add/subtract the x's that have the same power to get:
This is false, -5(3e-2) is not less than -2(6e+7)
Answer:
x=18, y=9
Step-by-step explanation:
The lines of y+3 and 12 look equal to each other. So do x-3 and 15. Because of this, we set each equal to each other and solve.
solving for x:
x-3 = 15
+ 3 +3
x=18
solving for y:
y+3=12
- 3 -3
y=9
hope this helps!!!
