Well if you are talking to me about the following graphic <span>http://contentlaunch.ple.platoweb.com/testimagedb/53/5377183edb46ae5c5177efb0f9dfbbd1 then we have to say that it would be 4,1. Right there you can find A. Hope this has helped you</span>
Answer:
Ok, first in our series we can see two numbers in the Sigma, one bellow 0, and other above, 4.
This means that the value of k will go from 0 to 4, then all the numbers in the sum are:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
So we have 5 terms in our series.
b) to see the sign in each term, we must solve the powers, remember that:
(-1)^n is -1 if n is odd, and is equal to 1 if n is even, so we have:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
= 1 -1/2 + 1/4 - 1/8 + 1/16.
So the sign in each term of the series alternates.
Answer:
x=-2/5
Step-by-step explanation:
4(-3x-1)=13x+6 ~ Distribute the 4 into the parenthesis
-12x-4 = 13x+6 ~ add 12x to both sides
-4= 25x + 6 ~ subtract 6 from both sides
-10 =25x ~ divide by 25
-10/25 = x ~ simplify the fraction by dividing the num. and den by 5
-2/5 =x
Given:
Room is 5 meters by 8 meters.
Measure of squaree tiles is 14-inch.
![\begin{gathered} \text{Area of the room=5}\times8 \\ \text{Area of the room=}40m^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BArea%20of%20the%20room%3D5%7D%5Ctimes8%20%5C%5C%20%5Ctext%7BArea%20of%20the%20room%3D%7D40m%5E2%20%5Cend%7Bgathered%7D)
![1m^2=1550inch^2](https://tex.z-dn.net/?f=1m%5E2%3D1550inch%5E2)
![\begin{gathered} \text{Area of each tile=14}\times14 \\ \text{Area of each tile=}196inch^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BArea%20of%20each%20tile%3D14%7D%5Ctimes14%20%5C%5C%20%5Ctext%7BArea%20of%20each%20tile%3D%7D196inch%5E2%20%5Cend%7Bgathered%7D)
![\begin{gathered} \text{Number of tiles to floor the room=}\frac{40\times1550}{196} \\ \text{Number of tiles to floor the room}=316.3265 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BNumber%20of%20tiles%20to%20floor%20the%20room%3D%7D%5Cfrac%7B40%5Ctimes1550%7D%7B196%7D%20%5C%5C%20%5Ctext%7BNumber%20of%20tiles%20to%20floor%20the%20room%7D%3D316.3265%20%5Cend%7Bgathered%7D)
Approximately 316 tiles are required to floor the room.