Answer:
option 4th is correct
x = 3, -1
Step-by-step explanation:
Set the next factor equal to 00.
x+1=0x+1=0
Subtract 11 from both sides of the equation.
x=−1x=-1
The final solution is all the values that make (x−3)(x+1)=0(x-3)(x+1)=0 true.
x=3,−1
Find the Roots (Zeros) f(x)=x^2-2x-3
f(x)=x2−2x−3f(x)=x2-2x-3
Set x2−2x−3x2-2x-3 equal to 00.
x2−2x−3=0x2-2x-3=0
Solve for xx.
Factor x2−2x−3x2-2x-3 using the AC method.
Consider the form x2+bx+cx2+bx+c. Find a pair of integers whose product is cc and whose sum is bb. In this case, whose product is −3-3 and whose sum is −2-2.
−3,1-3,1
Write the factored form using these integers.
(x−3)(x+1)=0(x-3)(x+1)=0
If any individual factor on the left side of the equation is equal to 00, the entire expression will be equal to 00.
x−3=0x-3=0
x+1=0x+1=0
Set the first factor equal to 00 and solve.
