Question

GIVING BRAINLIEST TO WHOEVER GETS IT RIGHT

Answer 1

Answer:

x=3             x = -1

Step-by-step explanation:

f(x) = x^2 − 2x − 3

Set the function equal to zero

0 = x^2 − 2x − 3

Factor

What two numbers multiply to -3 and add to -2

-3 *1 = -3

-3+1 = -2

0 = (x-3)(x+1)

Using the zero product property

x-3 =0     x+1 =0

x=3             x = -1

Answer 2

Answer:

option 4th is correct

x = 3, -1

Step-by-step explanation:

Set the next factor equal to 00.

x+1=0x+1=0

Subtract 11 from both sides of the equation.

x=−1x=-1

The final solution is all the values that make (x−3)(x+1)=0(x-3)(x+1)=0 true.

x=3,−1

Find the Roots (Zeros) f(x)=x^2-2x-3

f(x)=x2−2x−3f(x)=x2-2x-3

Set x2−2x−3x2-2x-3 equal to 00.

x2−2x−3=0x2-2x-3=0

Solve for xx.

Factor x2−2x−3x2-2x-3 using the AC method.

Consider the form x2+bx+cx2+bx+c. Find a pair of integers whose product is cc and whose sum is bb. In this case, whose product is −3-3 and whose sum is −2-2.

−3,1-3,1

Write the factored form using these integers.

(x−3)(x+1)=0(x-3)(x+1)=0

If any individual factor on the left side of the equation is equal to 00, the entire expression will be equal to 00.

x−3=0x-3=0

x+1=0x+1=0

Set the first factor equal to 00 and solve.