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3 years ago

Can someone help me

Mathematics

1 answer:

lyudmila [28]3 years ago

8 0

Answer:

29.3

Step-by-step explanation:

4x+12+5x+3x-4=360

Add the X's up & move the numbers w/out factors (X's) to the 360 side. This will look like 12x=352

Then, you divide each by 12, leaving you with x=29.3

Might be wrong, let me know and I will rework it.

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Please help me with this ty so much

OLEGan [10]

Answer:

3 and 1 seem right but no promises

Step-by-step explanation:

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3 years ago

Consider the exponential function f(x) = (15x). What is the value of the growth factor of the function

Marrrta [24]

The growth rate is the a value, or the number before the x value. The answer would be 15.

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3 years ago

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What is the GCF of 16s^3t, 40s^5, and 68t^2 A. 4 B.4s^3t C.8 D.8s^3t

labwork [276]

A is the answer to your question

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A decade-old study found that the proportion of high school seniors who felt that "getting rich" was an important personal goal

juin [17]

Answer: $H_0:p\leq0.72$

$H_a:p\neq0.72$

Step-by-step explanation:

Given : A decade-old study found that the proportion of high school seniors who felt that "getting rich" was an important personal goal was 72% .

Let 'p' be the new proportion of high school seniors who felt that "getting rich" was an important personal goal .

Claim : $p\neq0.72$

We know that the null hypothesis has equal sign.

Therefore , the null hypothesis for the given situation will be opposite to the given claim will be :-

$H_0:p=0.72$

And the alternative hypothesis must be :-

$H_a:p\neq0.72$

Hence, the null hypothesis and the alternative hypothesis that we would use for this test :

$H_0:p\leq0.72$

$H_a:p\neq0.72$

5 0

3 years ago

Various problems with data collection can cause some observations to be missing. Suppose a data set has 20 cases. Here are the v

mr Goodwill [35]

Answer:

a) Mean= 15, standard deviation= 5.1575

b) Mean= 15, standard deviation= 3.6469

c) See below

Step-by-step explanation:

(a) Compute the mean and standard deviation for the 10 cases for which x is not missing.

The mean using the ten known values is

$\bar x=\frac{17+6+12+14+20+23+9+12+16+21}{10}=15$

The standard deviation is

$\small s=\sqrt{\frac{(17-15)^2+(6-15)^2+(12-15)^2+(14-15)^2+(20-15)^2+(23-15)^2+(9-15)^2+(12-15)^2+(16-15)^2+(21-15)^2}{10}}=5.1575$

(b) Create a new data set with 20 cases by using imputation where you set the values for the 10 missing cases equal to the mean that you computed in the previous part. Compute the mean and standard deviation for this new data set with 20 cases.

The new data set would be

17, 6, 12, 14, 20, 23, 9, 12, 16, 21, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15

The new mean for this set of values would be then

$\bar x=\frac{\displaystyle\sum_{i=1}^{20}x_i}{20}=15$

The new standard deviation is now

$s=\sqrt{\frac{\displaystyle\sum_{i=1}^{20}(x_i-\bar x)^2}{20}}=3.6469$

(c) Summarize what you have learned about the possible effects of this type of imputation on the mean and the standard deviation.

Obviously, this way of imputation is somewhat arbitrary and will produce a set of data undoubtedly skewed.

It could possibly be a sensible way of imputing data if the amount of missing data is very little compared to the whole set, for example one or two data in a set of 100, but in this case we have 50% of missing data and it makes no sense this procedure.

4 0

3 years ago