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3 years ago

Can someone help me

Mathematics

1 answer:

lyudmila [28]3 years ago

8 0

Answer:

29.3

Step-by-step explanation:

4x+12+5x+3x-4=360

Add the X's up & move the numbers w/out factors (X's) to the 360 side. This will look like 12x=352

Then, you divide each by 12, leaving you with x=29.3

Might be wrong, let me know and I will rework it.

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A pudding recipe for 50 people calls for 4 cups of suger. Each bag contains 6 cups of suger how many bags of suger will be neede

Mashutka [201]

Answer:

4 bags

Step-by-step explanation:

50 people = 4 cups

300 people = 24 cups

24 cups ÷ 6 cups a bag = 4 bags

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2 years ago

In studies for a medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.

timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

$p = 0.03$

$q = 1 - 0.03 = 0.97$

The mean is

$\mu = np$

$\mu = 643 \times 0.03 = 19.29$

The standard deviation is

$\sigma = \sqrt{npq}$

$\sigma = \sqrt{643 \times 0.03 \times 0.97}$

$\sigma =4.33$

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

$P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \: \frac{24.5 - 19.29}{4.33} ) \\ = P( 0.97\: < \: z \: < \: 1.20) \\ = 0.051$

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

$P(X \: < \: 24.5) = P(z \: < \: \frac{24.5 - 19.29}{4.33} ) \\ = P(z \: < \: 1.20) \\ = 0.8849$

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

$P(X \: > \: 10.5) = P(z \: > \: \frac{10.5 - 19.29}{4.33} ) \\ = P(z \: > \: - 2.03)$

$= 0.9788$

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

$P(23.5 \: < \: X \: < \: 28.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \: \frac{28.5 - 19.29}{4.33} ) \\ = P( 0.97\: < \: z \: < \: 2.13) \\ = 0.1494$

3 0

3 years ago

Glenn needs to cut pieces of ribbon that are each 1 meter long to make ribbon key chains. If he has 6 pieces of ribbon that are

Jet001 [13]

Answer:

2/3

Step-by-step explanation:

Glenn needs to cut pieces of ribbon that are each 1 meter long to make ribbon key chains. If he has 6 pieces of ribbon that are each 1 dekameter long, how many 1−meter pieces of ribbon can he cut?

1 decametre = 10 metres

Hence,

10 meters = 6 pieces of ribbon

1 meter = x pieces

Cross Multiply

10x = 6

x = 6/10

x = 2/3 (1 meter pieces of ribbon)

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3 years ago

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What you know:

Mr. Adams spent $36.25 on 12.5 pounds.

All you do to find the cost per each pound is:

36.25/12.5

Your answer:
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3 years ago

All of the following are examples of composite numbers except which one?

Nataly [62]

<span>All of the following are examples of composite numbers except which one?

2.</span>

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3 years ago