How do I solve writing systems of equations in Algebra 1?
1 answer:
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Choice A is the answer which is the point (1,-1)
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How I got this answer:
Plug each point into the inequality. If you get a true statement after simplifying, then that point is in the solution set and therefore a solution. Otherwise, it's not a solution.
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checking choice A
plug in (x,y) = (1,-1)
This is true because -3 is equal to itself. So this is the answer.
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checking choice B
plug in (x,y) = (2,4)
This is false because 0 is not to the left of -3, nor is 0 equal to -3. We can cross this off the list.
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checking choice C
plug in (x,y) = (-2,3)
This is false because 7 is not to the left of -3, nor is 7 equal to -3. We can cross this off the list.
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checking choice D
plug in (x,y) = (3,4)
This is false because -2 is not to the left of -3, nor is -2 equal to -3. We can cross this off the list.
Answer:
x = 21
Explanation:
In a parallelogram, each two opposite angles are equal.
In the given parallelogram ABCD, we can note that angles A and C are opposite angles. This means that they have equal measures.
Therefore:
∠A = ∠C
x + 17 = 2x - 4
17 + 4 = 2x - x
x = 21
We can check:
angle A = 21 + 17 = 38°
angle C = 2(21) - 4 = 38°
They are equal
Hope this helps :)
x = 21
Explanation:
In a parallelogram, each two opposite angles are equal.
In the given parallelogram ABCD, we can note that angles A and C are opposite angles. This means that they have equal measures.
Therefore:
∠A = ∠C
x + 17 = 2x - 4
17 + 4 = 2x - x
x = 21
We can check:
angle A = 21 + 17 = 38°
angle C = 2(21) - 4 = 38°
They are equal
Hope this helps :)