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makvit [3.9K]
2 years ago
7

What is the median age

Mathematics
1 answer:
jeka57 [31]2 years ago
3 0
Median age is the age that divides a population into two numerically equally sized groups - that is, half the people are younger than this age and half are older. It is a single index that summarizes the age distribution of a population.
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lukranit [14]
D is the correct answer

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3 years ago
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What does x equal 7(2x+5)=4x -9 -x <br> PLEASEEEE HELPPPP ME
Gennadij [26K]

Answer: x=-4

Step-by-step explanation:

Given

7(2x+5)=4x-9-x

Expand parenthesis

14x+35=4x-9-x

Combine like terms

14x+35=3x-9

Subtract 35 on both sides

14x+35-35=3x-9-35

14x=3x-44

Subtract 3x on both sides

14x-3x=3x-44-3x

11x=-44

Divide 11 on both sides

11x/11=-44/11

x=-4

Hope this helps!! :)

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3 years ago
Perchlorate is a chemical used in rocket fuel. People who live near a former rocket-testing site are concerned that perchlorate
ser-zykov [4K]

Answer:

H_1 : \mu  > 24.5

Step-by-step explanation:

From the given information:

The sample size is 28

The population mean is 24.5 (ppb)

The sample mean is 225.3 (ppb)

Thus, the null and the alternative hypothesis can be computed as:

Null hypothesis:

H_o : \mu \le 24.5

Alternative hypothesis:

H_1 : \mu  > 24.5

8 0
3 years ago
A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From
lutik1710 [3]

Answer:

a) z = 1.645

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

\sqrt{n} = 17.12

\sqrt{n}^{2} = (17.12)^{2}

n = 293

The should sample at least 293 small claims.

8 0
3 years ago
Write without exponents (3p)^2
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(3p)(3p) or 3p x 3p. Cause the exponent means 3p times 3p
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