To solve this problem, we must recall that the formula
for velocity assuming linear motion:
v = d / t
Where,
v = velocity
d = distance
t = time
For condition 1: bus travelling on a level road
v1 = d1 / t1
<span>(v2 + 20) = (449 – d2) / 4 --->1</span>
For condition 2: bus travelling on a winding road
v2 = d2 / t2
<span>v2 = d2 / 5 --->2</span>
Combining equations 1 and 2:
(d2 / 5) + 20 = (449 – d2) / 4
0.8 d2 + 80 = 449 – d2
1.8 d2 = 369
d2 = 205 miles
Using equation 2, find for v2:
v2 = 205 / 5
v2 = 41 mph
Since v1 = v2 + 20
v1 = 41 + 20
v1 = 61 mph
Therefore
<span>the
average speed on the level road is 61 mph.</span>
Answer:
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Step-by-step explanation:
Answer:
23 x + 62
Step-by-step explanation:
Simplify the following:
5 (4 x + 12) + 3 x + 2
5 (4 x + 12) = 20 x + 60:
20 x + 60 + 3 x + 2
Grouping like terms, 60 + 20 x + 3 x + 2 = (20 x + 3 x) + (60 + 2):
(20 x + 3 x) + (60 + 2)
20 x + 3 x = 23 x:
23 x + (60 + 2)
60 + 2 = 62:
Answer: 23 x + 62
Answer:
Farmer Ed has 60 feet of fencing; and wants to enclose rectangular plot that borders on river: If Farmer Ed does not fence the side along the river; find the length and width of the plot that will maximize the area_ What is the largest area that can be enclosed? What width will maximize the area? The width, labeled x in the figure. (Type an integer or decimal ) What length will maximize the area? The length, labeled in the figure, is (Type an integer or decimal ) What is the largest area that can be enclosed? The largest area that can be enclosed is (Type an integer or decimal.)
You have 120 feet of fencing to enclose a rectangular plot that borders on a river.
Answer:
radius = 15 in.
circumference = 94.2 in.
Step-by-step explanation:
radius = diameter/2 = 30 in./2 = 15 in.
circumference = (pi)d = 3.14 * 30 in. = 94.2 in.
