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NeTakaya
3 years ago
12

Out of a total of 2,000 boxes, 40% were red. 50% of the red boxes were sold. a. How many red boxes were sold? Answer: _____ b. H

ow many boxes were not red in color? Answer: ______ plz help and teach me how to mark as brainliest so i can do that to people who help me
Mathematics
1 answer:
Natalija [7]3 years ago
3 0

Answer:

400 red boxes were sold

Step-by-step explanation:

Step 1: Our output value is 2000.

Step 2: We represent the unknown value with x.

Step 3: From step 1 above,2000=100%.

Step 4: Similarly, x=40%.

Step 5: This results in a pair of simple equations:

2000=100%

x=40%(2)

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

2000/x = 100%/40%

Step 7: Again, the reciprocal of both sides gives

x/2000 = 40%/100%

x=800

Therefore, 40% of 2000 is 800

and to find 50% just divide by 2

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–2x – 4 + 5x = 8
andriy [413]

Answer:

4

Step-by-step explanation:

-2x- 4 + 5x = 8

Collect like terms

-2x + 5x = 8 +4( when a variable crosses over equality sign it becomes either negative or positive depending on the sign)

3x = 12

Divide via by coefficient of x

X = 12/3

= 4

5 0
3 years ago
Read 2 more answers
What is -3 - 9n= 42 I can’t be negative
maw [93]

If you were to correctly simplify this equation, the answer would be a negative.

The answer is: n = -5

Here's how I got my answer:

Step 1: Add 3 to both sides. Which leaves us with -9n=42+3

Step 2: Simplify 42+3 to 45. Which leaves us with -9n = 45

Step 3: Divide both sides by -9. Which leaves us with n = -45/9

Step 4: Simplify -45/9, to get your answer, n = -5.

4 0
3 years ago
Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f
Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

P(A) = 0.1*0.8 + 0.25*0.2 = 0.13

Probability that a student is foreign and undergraduate:

10% of 80%. So

P(A \cap B) = 0.1*0.8 = 0.08

What is the probability that the student is an undergraduate?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154

0.6154 = 61.54% probability that the student is an undergraduate

8 0
3 years ago
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zalisa [80]
It’s is 1
wherever the vertex is, is the line of symmetry
5 0
2 years ago
Myles is working on his typing. He types for 3 minutes straight and is able to type 150 words. Determine how long it would take
erastova [34]
I think the answer is 6 because 900/150= 6 and 6X150 is 900 :)
6 0
3 years ago
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