Answer:
28°
Step-by-step explanation:
You're given that line DE and line FG are parallel and KL and FG are perpendicular. Then you can find out angle ∠BAC by using the vertical angles property: ∠BAC=62°. Then since KL and FG are perpendicular ∠ABC = 90°. So you find the angle ∠BCA by finding the sum of interior angles: 62+90+∠BCA=180, therefore ∠BCA is 28°. Finally, ∠x or ∠JCG = 28 because ∠JCG and ∠BCA are vertical angles and congruent.
Answer:
Graph the line using the slop and y-intercept, or two points.
Slope: 1
y-intercept: -2
x: 0, 0
y: -2, -2
(Sorry is this isn't the answer you are looking for)
42 - -84=-42
Hope this helps :)
I say its 11. Since the distance between the two points is 11.
(8)=ones place
(1)0=tens place
(1)00=hundreds place
(9)000=thousands place
The "1" beside the 8, is the tenths spot so you would round that part of the number.
Therefore the answer would be:
9120
