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ANEK [815]
2 years ago
11

A square has a perimeter of 40cm what is the length of each side​

Mathematics
2 answers:
docker41 [41]2 years ago
5 0

Answer:

length of each side : 10 cm

Step-by-step explanation:

all sides of squares are equal

thus, 4 sides = 40 cm

1 side = 40/10 cm

1 side = 10 cm

In-s [12.5K]2 years ago
4 0

Answer:

<h2><u><em>10 cm</em></u></h2><h2 />

Step-by-step explanation:

the formula of the perimeter of a square = 4 × (length of any one side)

we use the inverse formula

40 : 4 = 10 cm

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Find the area of the composite figure​
ehidna [41]
<h3>62.5 cm^2</h3>

The figure is a trapezoid, albeit not possessing the same lengths for the left and right sides. If I'm not mistaken, it has another name or term. But I forgot.

Anyway, to solve the problem, let us chop-chop or break the figure into two parts or two polygons that we are familiar with - a rectangle and a triangle. See the attached image for a clearer presentation.

After breaking the original polygon into two parts as portrayed by the red broken line, we are also going to divide the equivalent value of each side.

Remember, a rectangle has two pairs of common sides. Since the upper side of the polygon has a length of 10 cm, then, the length of the lower side (the side at the left side of the broken line) is 10, too. The same goes for the length of the left side which is 5 cm, and therefore the length of the broken line is 5 cm. Please refer to the attached image, particularly the figures in green.

From the standpoint of the triangle, based on thee figure, it has a height of 5 cm and a base of 5 cm (15 cm- 10 cm). Did you get it? If yes, let's continue.

Solving Time! :D

1. Solve for the area of the rectangle.

\begin{gathered}A_{rectangle}=L\times W\\=5\ cm \times 10\ cm\\=\bold{50\ cm^2}\end{gathered}

Arectangle=L×W=5 cm×10 cm=50 cm²

2. Solve for the area of the triangle.

\begin{gathered}A_{triangle}=\dfrac{b\times h}{2}\\=\dfrac{5\ cm\times5\ cm}{2}\\=\dfrac{25\ cm^2}{2}\\=\bold{12.5\ cm^2}\end{gathered}

Atriangle=2b×h=25 cm×5 cm=225 cm²=12.5 cm²

3. Combine (add) the two areas to find the area of the original figure.

\begin{gathered}A_{composite\ figure}=A_{rectangle}+A_{triangle}\\=50\ cm^2 +12.5\ cm^2\\=\bold{62.5\ cm^2}\end{gathered}

Acomposite figure=Arectangle+Atriangle=50 cm²+12.5 cm2=62.5 cm

If there's a Latex Error, Please click the second image attached below :)

4 0
2 years ago
This is the other one for that one i couldn't hold it
Zina [86]

Answer:

d

Step-by-step explanation:

8 0
3 years ago
Three dressers are placed side by side. One dresser is 5 feet 10 inches wide, another is 2 feet 11 inches wide, and the third is
lisov135 [29]
The answer is 13 feet 6 inches
7 0
3 years ago
Suppose a population of honey bees in Ephraim, UT has an initial population of 2300 and 12 years later the population reaches 13
Rama09 [41]

Answer:

common ratio: 1.155

rate of growth: 15.5 %

Step-by-step explanation:

The model for exponential growth of population P looks like: P(t)=P_i(1+r)^t

where P(t) is the population at time "t",

P_i is the initial (starting) population

(1+r) is the common ratio,

and r is the rate of growth

Therefore, in our case we can replace specific values in this expression (including population after 12 years, and  initial population), and solve for the unknown common ratio and its related rate of growth:

P(t)=P_i(1+r)^t\\13000=2300*(1+r)^{12}\\\frac{13000}{2300} = (1+r)^12\\\frac{130}{23} = (1+r)^{12}\\1+r=\sqrt[12]{\frac{130}{23} } =1.155273\\

This (1+r) is the common ratio, that we are asked to round to the nearest thousandth, so we use: 1.155

We are also asked to find the rate of increase (r), and to express it in percent form. Therefore we use the last equation shown above to solve for "r" and express tin percent form:

1+r=1.155273\\r=1.155273-1=0.155273

So, this number in percent form (and rounded to the nearest tenth as requested) is: 15.5 %

6 0
3 years ago
(x + 2)*(x^2 -2*x+4) - (x^3 -12)
Ivahew [28]

Answer:

  • \large{ \boxed{ \tt{20}}}

- Please see the attached picture for full solution!:)

------------ HappY LearninG <3 -----------

3 0
2 years ago
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