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3 years ago

Convert 1 mm to meters using scientific notation. Include units in your answer.

Physics

1 answer:

irinina [24]3 years ago

7 0

Answer: The answer in scientific notation with the unit included is (1 × 10^-3m.)

Explanation:

In the field of physics, when working with too large or too small numbers, such can be expressed with the use of scientific notation. This helps to eliminate huge or ambiguous numbers with significant units. It is written is such a way that the first number is greater than or equal to 1 and less than 10 which is then multiplied by a factor of 10.

Units are symbols that are used to represent a measurement For example the unit of meters is (m).

Converting 1mm to m:

1000millimeters = 1meter

1 millimetre = X

Making X the subject of formula,

X = 1 ×1 /1000

X = 0.001m

Therefore expressing X in scientific notation is

1 × 10^-3meter (m)

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Two bar magnets are placed side by side.

Jobisdone [24]

The question is wrongly written

Explanation:

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3 0

4 years ago

If you weigh 150 lbs. on the surface of Earth, how much would you weigh on Venus? On Mars?

Ghella [55]

Answer:

weight on Venus = 604.15 N

weight on Venus = 252.01 N

Explanation:

Given:

Weight on the earth , W = 150 lbs

now,

1 lbs = 4.45 N

thus,

W = 150 × 4.45 = 667.5 N

now, mass on the earth, m = 667.5/9.8 = 68.11 kg

now,

⇒ weight on Venus,

the acceleration due to gravity on venus = 8.87 m/s²

thus,

weight on Venus = mass × acceleration due to gravity on venus

weight on Venus = 68.11 × 8.87 = 604.15 N

⇒ weight on mars,

the acceleration due to gravity on mars = 3.70 m/s²

thus,

weight on Venus = mass × acceleration due to gravity on venus

weight on Venus = 68.11 × 3.70 = 252.01 N

7 0

4 years ago

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horsena [70]

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5 0

3 years ago

Read 2 more answers

A conveyor belt is used to send burgers through a grill- ing machine. If the grilling machine is 1.2m long and the burgers requi

puteri [66]

Answer:

$Rate = 1.71 burger/min$

Explanation:

Length of the conveyor belt is given as

$L = 1.2 m$

time taken to cook one burger is given as

$t = 2.8 min = 168 s$

now we can find the speed of the belt as

$v = \frac{distance}{speed}$

$v = \frac{1.2}{168}$

$v = 7.14 \times 10^{-3} m/s$

Now we know that the distance between two burgers is given as 25 cm

$d = 0.25 m/burger$

now the production rate of burgers is given as

$Rate = \frac{v}{d}$

$Rate = \frac{7.14 \times 10^{-3} m/s}{0.25 m/burger}$

$Rate = 0.0286\frac{burger}{sec}$

$Rate = 0.0286\times 60\frac{burger}{min}$

$Rate = 1.71 burger/min$

8 0

3 years ago

Air at 30°C and 2MPa flows at steady state in a horizontal pipeline with a velocity of 25 m/s. It passes through a throttle valv

erastovalidia [21]

Answer:

$V_2=159.9\ m/s$

$T_2=290.6K$

Explanation:

At initial condition

P=2 MPa

T=30°C

V=25 m/s

At final condition

P=0.3 MPa

Now from first law for open system

$h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}$

We know that for air

h= 1.010 x T KJ/kg

$1.01\times 303+\dfrac{25^2}{2000}=1.01\times T+\dfrac{V_2^2}{2000}$ -----1

Now from mass balance

$\rho_1A_1V_1=\rho_2A_2V_2$

We also know that

$\rho=\dfrac{P}{RT}$

$\dfrac{P_1}{RT_1}V_1=\dfrac{P_2}{RT_2}V_2$

$\dfrac{2}{R\times 303}\times 25=\dfrac{0.3}{RT_2}V_2$

$T_2=1.81V_2$ ----------2

Now from equation 1 and 2

$V_2^2+3673.749V-612916.49=0$

So we can say that

$V_2=159.9\ m/s$

This is the outlet velocity.

Now by putting the values in equation 2

$T_2=1.81\times 159.9$

$T_2=290.6K$

This is the outlet temperature.

4 0

4 years ago