THE ANSWER IS B THE CEASE TO EXIST WHEN LAVED IN LIQUDI hope that helped
Answer
3
Explanation:
x=
<em>t + 1/2 </em>
<em />
If velocity is constants there is no acceleration therefore acceleration will equal zero.
Answer:
No, the truck will not cross the barrier.
The closeness of the truck to the barrier is of 21.875 m
Solution:
As per the question:
Velocity of the truck, v = 25.0 m/s
Acceleration of the truck, a = - 4 
Now,
Since, the barrier at a distance of 100 m. Thus in order to check whether the truck hit the barrier or not, we will see the distance, d it covers by using the kinematic eqn:

Final velocity, v' = 0 m/s
Initial velocity = v
Now,


d = 78.125 m
Thus the truck will not cross the barrier.
Distance between the barrier and the truck:
100 - 78.125 = 21.875 m
The volume of the cylindrical can is given by:
V = πr²h
V = volume, r = base radius, h = height
Differentiate both sides of the equation with respect to time t. The radius r doesn't change over time, so we treat it as a constant:
dV/dt = πr²(dh/dt)
Given values:
dV/dt = -527in³/min
r = 8in
Plug in and solve for dh/dt:
-527 = π(8)²(dh/dt)
dh/dt = -2.62in/min
The height of the water is decreasing at a rate of 2.62in/min