The height at time t is given by
h(t) = -4.91t² + 34.3t + 1
When the ball reaches maximum height, its derivative, h'(t) = 0.
That is,
-2(4.91)t+34.3 = 0
-9.82t + 34.3 = 0
t = 3.4929 s
Note that h''(t) = -9.82 (negative) which confirms that h will be maximum.
The maximum height is
hmax = -4.91(3.4929)² + 34.3(3.4929) + 1
= 60.903 m
Answer:
The ball attains maximum height in 3.5 s (nearest tenth).
The ball attains a maximum height of 60.9 m (nearest tenth)
G.P.E = mgh
Weight = mg = 200N
So G.P.E = 200 * 2 = 400 Joules
Insulator, or a semi-conductor. A semi-conductor is a specific type of insulator.
Answer:
30 degrees Celsius
Explanation:
With unsaturated adiabatic lapse rate water vapour does not have to change state from gaseous to liquid.
