Question

Please help

Answer 1

Answer:

we get $\mathbf{gf(2)=-\frac{1}{3}}$

Step-by-step explanation:

We are given:

$f(x)=1-2x\\g(x)= \frac{1}{x}\\h(x)=x^3+1$

We need to find value of $gf(2)$

$gf(2)=g(f(2))$

First putting f(x) inside of g(x) and then putting x=2

$gf(x)=g(f(x))\\gf(x)=\frac{1}{1-2x}$

Now putting x=2 to find $gf(2)$

$gf(x)=\frac{1}{1-2x}\\gf(2)=\frac{1}{1-2(2)}\\gf(2)=\frac{1}{1-4}\\gf(2)=\frac{1}{-3}\\gf(2)=-\frac{1}{3}$

So, we get $\mathbf{gf(2)=-\frac{1}{3}}$