Answer:
Mixed economy.
Explanation:
In the country of Mashwen, the state owns key industries such as energy and transportation. The rest of the industries are privately owned. Mashwen is a <u>Mixed</u> economy.
Mixed economy: It is a shared economy system, which has equal role of private enterprises and public enterprises. In the current global market, most of the economy are mixed economy. It allow private enterprises with equal opportunity to participate in the market, it create healthy competition among different player and buyer can have variety of product at low price.
Answer:
C. The system is functioning correctly and providing accurate information
Explanation:
Reliability refers to the ability of a system or a machine to perform its intended function with minimal or nil breakdown. Consistency and validity of data from the performance of a system or a piece of equipment indicate its reliability. It is the possibility of failure-free operation of a system.
Reliability will, therefore, ensure a system is performing its function with minimal interruptions resulting from failures. It guarantees consistency in the results from operations. With reliability, production happens when it is needed.
Answer:
c is the answer to the question
Explanation:
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Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate, 
= 6 boats per hour.
Service rate, 
= 10 boats per hour.
Probability of zero boats in the system,![\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\}](https://tex.z-dn.net/?f=%5Cmathrm%7BPO%7D%3D1%20%2F%5C%7B%5B%281%20%2F%200%20%21%29%20%5Ctimes%286%20%2F%2010%29%200%2B%281%20%2F%201%20%21%29%20%5Ctimes%286%20%2F%2010%29%201%5D%2B%5B%286%20%2F%2010%29%202%20%2F%282%20%21%20%5Ctimes%281-%286%20%2F%282%20%5Ctimes%2010%29%29%29%5D%5C%7D)
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
= ![[\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385](https://tex.z-dn.net/?f=%5B%5C%7B6%20%5Ctimes%2010%20%5Ctimes%286%20%2F%2010%29%202%5C%7D%20%2F%5C%7B%282-1%29%20%21%20%5Ctimes%28%282%20%5Ctimes%2010%29-6%29%202%5C%7D%5D%20%5Ctimes%200.5385)
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
Answer:
the portfolio´s beta is 1.65
Explanation:
when the individual calculation of beta has been given, is possible to aggregate them as a weigthed average, so it is possible to apply te next formula
where w is the weigthed value for each asset, in this particular case we have:
so with this result we get 1.65
