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ella [17]
3 years ago
6

the grade point average collected from a random sample of 150 students. assume that the population standard deviation is 0.78. f

ind the margin of error if c = 0.98.
Computers and Technology
1 answer:
salantis [7]3 years ago
3 0

Answer:

E =  14.81\%

Explanation:

Given

n = 150

\sigma = 0.78

c = 0.98

Required

The margin of error (E)

This is calculated as:

E = z * \frac{\sigma}{\sqrt{n}}

When confidence level = 0.98 i.e. 98%

The z score is: 2.326

So, we have:

E = 2.326 * \frac{0.78}{\sqrt{150}}

E = 2.326 * \frac{0.78}{12.247}

E =  \frac{2.326 *0.78}{12.247}

E =  \frac{1.81428}{12.247}

E =  0.1481

Express as percentage

E =  14.81\%

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