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Vesna [10]
3 years ago
9

What is the common difference for this arithmetic sequence 45,40,35,30,25,...

Mathematics
2 answers:
Elza [17]3 years ago
8 0

Answer:-5

Step-by-step explanation:

HACTEHA [7]3 years ago
6 0

Answer:

Step-by-step explanation:t

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In circle L, points E and F lie on the circle such that E, F and L are not collinear. If LE, LF and EF are drawn then which of t
frozen [14]

Answer:

<u>option (2) it is and isosceles triangle. </u>

Step-by-step explanation:

In circle L, points E and F lie on the circle such that E, F and L are not collinear

If LE, LF and EF are drawn

So, LE = EF = the radius of the circle L

So, LEF is an isosceles triangle.

The answer is option (2) it is and isosceles triangle.

8 0
3 years ago
85% of what number is 10.2
Free_Kalibri [48]

<em>Answer:</em>

<em>n = 12</em>

<em>Step-by-step explanation:</em>

<em>85%×n = 10.2</em>

<em>85n/100 = 10.2</em>

<em>85n = 1020</em>

<em>n = 1020 : 85</em>

<em>n = 12</em>

7 0
3 years ago
The scale on a map is 1 in. :25 mi. Your measure 6.5 in. Between two towns. What is the actual distance?
pshichka [43]

Answer:

162.5mi

Step-by-step explanation:

If the scale of the map is 1in:25mi, and you measure 6.5in between two twoms, then the real distance would be 6.5in*25mi = 162.5mi.

6 0
3 years ago
How are coordinate planes the same ???? <br> 22 points if u can answer
Natalka [10]

Answer: Its a trick question

Step-by-step explanation:

I did this yesterday

3 0
3 years ago
Read 2 more answers
Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0
Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . x^{2}e^{-x}+2y^{2}-xy"

Answer : \frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

Step-by-step explanation:

From the expression  x^{2}e^{-x}+2y^{2}-xy" y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\

for the expression \frac{d}{dx}(x^{2}e^{-x}) we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\.

if we make dy/dx  subject of formula we arrive at

(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

5 0
3 years ago
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