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3 years ago

Solve 3/4x = -6 showing each step explaining each property used.

Mathematics

2 answers:

polet [3.4K]3 years ago

4 0

Well, since it's already set up, all we do is divide -6 by 3/4 to get our x
So that means x=-8

zmey [24]3 years ago

3 0

Hi there,
We can start off by first rewriting the equation:
3/4x = -6
First, we use the multiplication property of equality to multiply the reciprocal of 3/4, which is 4/3 to -6.
x = -6 × 4/3
Now, we just simplify,
x = -24/3 => x = -8
Therefore, the answer to your query is x = -8. Hope this helps!

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helen has 30 tickets.Gina has 20 more tickets thank helen.what percent of tickets must Gina give helen so that both of them can

iren [92.7K]

Helen = 30 T (T = tickets)
Gina = 30 + 20 = 50 T

20% of 50 = 10

30 + 10 = 404
50 - 10 = 40

Gina must give 20% of her tickets for them to have equal amount of tickets.

Hope this helps!!

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3 years ago

Amran is helping her sixth grade classmates get ready for their math test by making them identical Packages of pencils and calcu

Sholpan [36]

Answer:

Step-by-step explanation:

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3 years ago

What is the value 0.25 ? The 2 has a value of 2 _____________ or 0.2 The 5 has a value of 5 ______________ or 0.05

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Answer:

NUT?

Step-by-step explanation:

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3 years ago

Read 2 more answers

The figure is made up of two shapes, a semicircle and a rectangle.What is the exact perimeter of the figure?

grandymaker [24]

Perimeter of circular area = πr = 3.14 * 10 = 31.4 mm

Perimeter of rectangular area = 30 + 20 + 30 = 80 mm

Total Perimeter = 80 + 31.4 = 111.4

In short, Your Answer would be 111.4 mm

Hope this helps!

7 0

2 years ago

Read 2 more answers

Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .