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Katena32 [7]
3 years ago
6

When the volume of a gas is changed from mL to 852 mL the temperature will change from 315c to 452c

Chemistry
1 answer:
zhenek [66]3 years ago
4 0

Answer:

The starting volume is 691 mL

Explanation:

The compete question is:

When the volume of a gas is changed from ___ mL to 852 mL, the temperature will change from 315 °C to 452 °C. What is the starting volume?

Write Charles Law and substitute values in:

   V1 / T1 = V2 / T2

    V1 / 588 K = 852 mL / 725 K

   V1 (725 K) = (852 mL) (588 K)

   V1 = 691 mL

Note the large °C values, trying to get you to forget to add 273. Remember, only Kelvin temperatures are allowed in the calculations.

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if only 0.264 g of ca(oh)2 dissolves in enough water to give 0.178 l of aqueous solution at a given temperature, what is the ksp
Maurinko [17]

The ksp value for calcium hydroxide at this temperature is 5.20 × 10⁻⁶.

<h3>What is ksp?</h3>

Ksp is an equilibrium constant of a solid substance dissolved in a liquid solution.

Given that, the volume of water is 0.178 l, 0.264 g of Ca(OH)² dissolves in enough water

The solution equilibrium is

Ca(OH)² = Ca + 2OH

The molar solubility is

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The ksp value will be

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Putting the values in the formula

(0.0109) x (2 x 0.0109)² = 5.20 × 10⁻⁶.

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1 year ago
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Answer:

The structures are shown in the figure.

Explanation:

The primary hydrogens are those which are attached to primary carbon.

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Primary carbons is bonded to three hydrogens.

In order to draw such structure we will draw structures which will have carbon with three hydrogens or no hydrogens (quaternary)

The structures are shown in the figure with clear marking.

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3 years ago
A student explained to the class that helium has 8 valence electrons because it is in group 18. Is the student correct?
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zmey [24]

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