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3 years ago

Classify the following atom as excited, ground state, or not possible. 1s^2 2s^2 2p^6 3p^1

1 answer:

8 0

According to Pauli's exclusion principle, the energy levels of the subshells should be arranged in an increasing manner. The energy of each subshell can be computed. In the sequence, the given subshells are arranged in a correct order. 30p allows 6 electrons at maximum so this configuration is considered as ground state

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The pressure of 1 mol of gas is decreased to 0.5 atm at 273 K. What happens to the molar volume of the gas under these condition

m_a_m_a [10]

Answer : The molar volume of the gas will be, 44.82 L

Solution :

Using ideal gas equation,

$PV=nRT$

where,

n = number of moles of gas = 1 mole

P = pressure of the gas = 0.5 atm

T = temperature of the gas = 273 K

R = gas constant = 0.0821 Latm/moleK

V = volume of the gas.

Now put all the given values in the above equation, we get the molar volume of the gas.

$(0.5atm)\times V=(1mole)\times (0.0821Latm/moleK)\times (273K)$

$V=44.82L$

Therefore, the molar volume of the gas will be, 44.82 L

6 0

3 years ago

A buffer solution contains 0.306 M C6H5NH3Br and 0.418 M C6H5NH2 (aniline). Determine the pH change when 0.124 mol HCl is added

Ulleksa [173]

Answer: The pH change of the buffer is 0.30

Explanation:

To calculate the pH of basic buffer, we use the equation given by Henderson Hasselbalch:

$pOH=pK_b+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})$

$pOH=pK_b+\log(\frac{[C_6H_5NH_3^+]}{[C_6H_5NH_2]})$ .....(1)

We are given:

$pK_b$ = negative logarithm of base dissociation constant of aniline = 9.13

$[C_6H_5NH_3^+]=0.306M$

$[C_6H_5NH_2]=0.418M$

pOH = ?

Putting values in equation 1, we get:

$pOH=9.13+\log(\frac{0.306}{0.418})\\\\pOH=8.99$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\pH_{initial}=14-8.99=5.01$

To calculate the molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles hydrochloric acid solution = 0.124 mol

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of HCl}=\frac{0.124}{1L}\\\\\text{Molarity of HCl}=0.124M$

The chemical reaction for aniline and HCl follows the equation:

$C_6H_5NH_2+HCl\rightarrow C_6H_5NH_3^++Cl^-$

Initial: 0.418 0.124 0.306

Final: 0.294 - 0.430

Calculating the pOH by using using equation 1:

$pK_b$ = negative logarithm of base dissociation constant of aniline = 9.13

$[C_6H_5NH_3^+]=0.430M$

$[C_6H_5NH_2]=0.294M$

pOH = ?

Putting values in equation 1, we get:

$pOH=9.13+\log(\frac{0.430}{0.294})\\\\pOH=9.29$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\pH_{final}=14-9.29=4.71$

Calculating the pH change of the solution:

$\Delta pH=pH_{initial}-pH_{final}\\\\\Delta pH=5.01-4.71=0.30$

Hence, the pH change of the buffer is 0.30

8 0

3 years ago

What products would you expect from the reaction of ammonia and sulfuric acid in aqueous solution? 2nh3(aq)+h2so4(aq)→ ?

arsen [322]

From the reaction of ammonia and sulfuric acid in aqueous solution 2nh3(aq)+h2so4(aq)→ (NH4)2SO4 + H2O will be formed.Sulfuric acid is diprotic so is able to give up 2 H+ ions. It is an acid-base neutralisation reaction forming ammonium sulphate as the salt. 2NH3 with H2SO4 reacts in a neutralization reaction to form salt water, with ammonium sulphate left behind to crystallize after evaporation.

5 0

2 years ago

3. Give an example of how carbon is transferred frem being in a living to a non-living organism.

slavikrds [6]

Answer:

Carbon moves from living things to the atmosphere. Each time you exhale, you are releasing carbon dioxide gas (CO2) into the atmosphere. Animals and plants need to get rid of carbon dioxide gas through a process called respiration. Carbon moves from fossil fuels to the atmosphere when fuels are burned.

4 0

3 years ago

How many significant numbers are there in 40.00

muminat

The answer to this is 4.

3 0

3 years ago

Read 2 more answers