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kirill115 [55]
3 years ago
14

As a photon from the Sun's core interacts with an atom or ion, the photon gives up its energy to the particle. But the excited p

article gives up this excess energy as another photon. Thus the core's energy is carried outward in a process called _____ transport.
Physics
1 answer:
Natalka [10]3 years ago
8 0

Answer:

Radiative transport

Explanation:

Radiative transportation takes place extensively in the core of the sun. It produces solar energy which are emitted outward from the core of the sun, and it comprises more than 70% of the sun's heat energy. At the core of the sun, the process of nuclear fusion takes where the hydrogen atoms combines with one another, and forms helium, and during this process, it releases a large amount of energy. The photons continuously interacts with the ions (or atoms) and releases this energy to the particles and the excited particles converts the excess amount of energy into another photon which are carried outward by the process of radiative transport.

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Charlie Brown kicks a football at 24.5 m/s at 35.0. What is the maximum height of the ball?
lozanna [386]

Answer:

d = 10.076 m

Explanation:

We need to obtain the velocity of the ball in the y direction

Vy  = 24.5m/s * sin(35) = 14.053 m/s

To obtain the distance, we use the formula

vf^2 = v0^2 -2*g*d

but vf = 0

d = -vo^2/2g

d = (14.053)^2/2*(9.8) = 10.076 m

5 0
3 years ago
Decide whether the attribute describes Earth, Venus, or both Earth and Venus.
masha68 [24]

1). both

2). Venus

3). Venus catastrophically; Earth too but much less.

4). Earth

5). Earth

6). Venus (It would be pretty hard for US to mistake Earth for a star.)


3 0
3 years ago
Read 2 more answers
An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after
KatRina [158]

Answer:

E = kQs/r.r

Explanation:

Where E is the magnitude of electric field...

k is called Columb's Constant. It has a value of 8.99 x 109 N m2/C2.

Qs is the magnitude of the source charge...

and r is the magnitude of distance between source and target...

(When electron comes to rest Δt the magnitude of Electric field E become zero momentarily but later achieves the maximum value...)

5 0
3 years ago
A ball is thrown downward at 12 m/s from a windowsill 35 m above the ground. At the same time, another ball is thrown upward at
wariber [46]

Answer:

The second ball lands 1.5 s after the first ball.

Explanation:

Given;

initial velocity of the ball, u = 12 m/s

height of fall, h = 35 m

initial velocity of the second, v = 12 m/s

Time taken for the first ball to land;

t = \sqrt{\frac{2h}{g} }\\\\t =\sqrt{ \frac{2*35}{9.8}}\\\\t = 2.67 \ s

determine the maximum height reached by the second ball;

v² = u² -2gh

at maximum height, the final velocity, v = 0

0 = 12² - (2 x 9.8)h

19.6h = 144

h = 144 / 19.6

h = 7.35 m

time to reach this height;

t_1 = \sqrt{\frac{2h}{g} }\\\\t_1 =  \sqrt{\frac{2*7.35}{9.8}}\\\\t_1 = 1.23 \ s

Total height above the ground to be traveled by the second ball is given as;

= 7.35 m + 35m

= 42.35 m

Time taken for the second ball to fall from this height;

t_2 = \sqrt{\frac{2h}{g} }\\\\t_2 = \sqrt{\frac{2*42.35}{9.8} }\\\\t_2 = 2.94 \ s

total time spent in air by the second ball;

T = t₁ + t₂

T = 1.23 s + 2.94 s

T = 4.17 s

Time taken for the second ball to land after the first ball is given by;

t = 4.17 s -  2.67 s

T = 1.5 s

Therefore, the second ball lands 1.5 s after the first ball.

4 0
3 years ago
What are the factors of weight
Tatiana [17]
The answer to your question is body weight,<span> </span>body heat and muscle mass<span>.
Hoped I Helped!</span>
5 0
3 years ago
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