Answer:
The answer to your question is T2 = 580.5 °K
Explanation:
Data
Temperature 1 = T1 = 273°K
Pressure 1 = P1 = 388 kPa
Pressure 2 = P2 = 825 kPa
Temperature 2 = ?
Process
1.- Use the Gay-Lussac law
P1/T1 = P2/T2
-Solve for T2
T2 = P2T1/P1
-Substitution
T2 = (825)(273) / 388
-Simplification
T2 = 225225 / 388
-Result
T2 = 580.5 °K
Volume will decrease if the heat remains constant
Answer:
Wavelength of sound in the pipe is 6.0 m
Explanation:
As we know that closed pipe is given to us so here at open end it will form antinode while at closed end it will form Node
Here we know that in closed pipes on odd harmonics will exist
so here for third harmonic we have
where L = length of the pipe
so we have
Carson's Rule says:
FM occupied bandwidth =
(2) · (Peak deviation + Highest modulating frequency)
so
FM bw = (2) · (60 kHz + 15 kHz)
FM bw = (2) · (75 kHz)
FM bw = 150 kHz
(I used to eat this stuff for lunch, but it's been almost 40 years. Thanks for taking me back. Those were the good old days.)
The correct answer is conner because he has more than everyone else 4 is more than 3.5, 2.5, and 3
