The first-serve percentage of a
tennis player in a match is normally distributed with a standard deviation of
4.3%. If a sample of 15 random matches of
the player is taken, the mean
first-serve percentage is found to be 26.4%. The margin of error of the sample
mean is 83.71%.
Answer:
it basically says to write an equation Wich would be 22 and 12 using distributive property and is multiplication
Step-by-step explanation:
so... 22
x12
----
264
Answer:
<h2>no solution</h2>
Step-by-step explanation:
Answer:
Step-by-step explanation:
Factorise in order to reveal factors.
Answer:
center:
(-0.25, 5)
foci :
(-0.25, 0.158771) | (-0.25, 9.84123)
vertices :
(-0.25, -0.59017) | (-0.25, 10.5902)
wolframramalpha
