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MrRa [10]
3 years ago
10

What is the difference between refference and indicator electrode​

Chemistry
1 answer:
romanna [79]3 years ago
5 0

Answer:

The key difference between indicator electrode and reference electrode is that indicator electrode responds to changes in the activity of the analyte, whereas reference electrode does not respond to changes, and its response is stable.

Explanation:

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What can you tell by tracking oxidation numbers?
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<u>Answer</u>:

By tracking oxidation numbers we can identify the number electron in the atom

<u>Explanation</u>:

Tracking of electrons helps us to know when and how many electrons get transferred from one atom to other atom . Oxidation  referred as the “loss of one or more electrons” by an atom. When the oxidation number of an element increases, there is a loss of electrons and that element is being oxidized. Oxidation numbers are usually written with the sign (+plus or −minus) followed by the magnitude, which is the opposite of charges on ions. In their elemental stage oxidation number of an atom is zero.  

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nuclear reactions can be written out in equation form with information about the nuclei that are produced. in one to two sentenc
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3 years ago
In his proposed model of the atom, J.J. Thomson imagined the atom contained _____.
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Identify the double displacement reaction. 3Pb 2h 3PO 4 ⟶ 3H 2 Pb 3(PO 4) 2 2NO 2 ⟶ 2O 2 N 2 2NaBr Ca(OH) 2 ⟶ CaBr 2 2NaOH 2NH 3
IRISSAK [1]

Reaction 3 is the double displacement reaction.

Double displacement reaction occurs when the negatively and the positively charged ions of the compounds interchange their position when the new compound in the product is formed.

<h3>Which is a double displacement reaction?</h3>

In the <u>first reaction</u>, the element lead (Pb) is not an ion and no exchange of the cations or the anions occurs hence it is not a double displacement reaction.

In the <u>second reaction</u>, one compound is getting split into two new compounds and is a decomposition reaction.

In the <u>third reaction</u>,  \rm Br^{-} in \rm 2NaBr and \rm (OH)_{2} in \rm Ca(OH)_{2} are anions and cations and exchanges their places to produce two new compounds  \rm CaBr_{2} + 2NaOH.

In the <u>fourth reaction</u>, a single compound is generated as the result of the combination reaction and hence, it is not the double displacement reaction.

Therefore, \rm 2NaBr + Ca(OH)_{2} \rightarrow CaBr_{2} + 2NaOH is the double displacement reaction.

Learn more about double displacement reaction here:

brainly.com/question/10091171

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2 years ago
Which factor impacts the possible number of ways in which different atoms can be put together?
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