Explanation:
For a compound to show hydrogen bonding it is necessary that the hydrogen atom of the compound should be attached to more electronegative atom like fluorine, oxygen or nitrogen.
For example,
,
and
all these compounds contain an electronegative atom attached to hydrogen atom.
Therefore, these pure compounds will exhibit hydrogen bonding.
Thus, we can conclude that out of the given options
,
and
are the pure compounds which will exhibit hydrogen bonding.
Answer:
A = 2
B = 1
Explanation:
The atomic number of lithium is 3.
Its atomic mass is 7 amu.
It is present in group group 1.
It has one valance electron.
Lithium is alkali metal it form salts.
It is silvery soft metal. It has lowest density as compared to all other metals.
It react vigorously with water.
It is used in rechargeable batteries which are used in camera, mobile, laptops etc.
The electronic configuration of Li:
Li₃ = 1s² 2s¹
Thus,
A = 2
B = 1
The mass percent of oxygen is 32.82%.
<h3>What is a noble gas?</h3>
A noble gas is member of group 18 in the periodic table. The members of this group are known not to be reactive and they do not easily form compounds. However, there have been few compounds of the members of group 18 that have been reported.
Let us now calculate the relative molecular mass of xenon tetraoxide.
Xe + 4 (O)
131 + 4(16) = 195
Given that the mass of oxygen in the compound is 64, the mass percent of oxygen in xenon tetroxide is obtained from;
64/195 * 100/1
= 32.82%
Learn more about mass percent:brainly.com/question/5394922
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The researcher may first weight the beaker with water and then start to heat the water to a constant temperature, for example 30 °C and then start adding salt and stirring. He should add salt slowly until solid salt starts to become visible and the solution starts becoming cloudy. When this happens, he should quickly weigh the beaker. The increase in mass is the mass of salt dissolved at that temperature.
The procedure is then repeated but at an increased temperature until 5-6 temperatures have been tested.