Answer:
N = n× l
N = number of entities
n= moles
l = Avogadro's constant = 6.023 × 10^23
3.01 × 10^ 23 = n * 6.023 × 10^23
n = 3.01 × 10^23/6.023 × 10^23
n= 0.5moles
Molar mass = mass/ number of moles
Molar mass = 56
mass = 56 × 0.5
= 28g
Hope this helps.
its C) 113.21g
u just add all the masses
If i am not mistaken ,
density = mass / volume
density = 7.87 g/cm3
volume = 2.5 cm3
thus ,
mass = density x volume
7.87 g/cm3 x 2.5 cm3 = 19.675 g
Assuming the molar mass of oxygen is 18.01, you only need 16 grams (B) of oxygen because the molar mass of hydrogen is about 1 gram.
16+1+1=18
Answer:
V₂ = 8.36 L
Explanation:
Given data:
Initial volume of gas = 5.00 L
Initial temperature = -50.0°C (-50 + 273 = 223 k)
Final temperature = 100°C (100+273 = 373 k)
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 5.00 L × 373 K / 223 K
V₂ = 1865 L.K / 223 K
V₂ = 8.36 L
