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alekssr [168]
3 years ago
9

Sin( X+Y ) = cos( X−Y ) = 1, find the value of X and Y.

Mathematics
1 answer:
iris [78.8K]3 years ago
7 0

answer x = 225 and y = -135

Step-by-step explanation:

x+y = 90 and x= 90-y and x -y = 360 so 90-y -y = 360

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A line segment with endpoints A = (3, 0) and B = (7,0). Then, plot all points
eduard

Answer:

C(0,6)

Step-by-step explanation:

1) find the length of the base of the triangle

AB = 7-3 = 4

2) find the the height of the triangle

A = (base x height)/2

A x 2 = base x height

height = (A x 2)/base

height = (12 x 2)/4 = 6

3) find the equation of the line that passes threw the points AB

the two points have the same y so the equation of the line is

y = 0

4) use the formula of the distance between a point and a line to find C

|ax+by+c|/√a^2 + b^2 = distance

x = 0  

y = 6

C (0,6)

5 0
2 years ago
Michael, whose eyes are five feet off the ground, is standing 26 feet away from the base of a building, and he looks up at a 65°
yawa3891 [41]

Answer:

Dear user,

Answer to your query is provided below

The building is 60.77 ft tall.

Step-by-step explanation:

Explanation is provided below in the image attached

3 0
2 years ago
Determine the measure of angle j: angle k: & angle: l
Vikki [24]

Answer:

17=J

L= 180-17

 = 163

K=163

L=163

J=17

Step-by-step explanation:

3 0
2 years ago
4 times a number is 16​
andrey2020 [161]

Answer:

4 times 4 equals 16

Step-by-step explanation:

4 times 1= 4

4 times 2= 8

4 times 3= 12

4 times 4= 16

you add 4 after each result.

4 0
3 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
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