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3 years ago

Sin( X+Y ) = cos( X−Y ) = 1, find the value of X and Y.

Mathematics

1 answer:

iris [78.8K]3 years ago

7 0

answer x = 225 and y = -135

Step-by-step explanation:

x+y = 90 and x= 90-y and x -y = 360 so 90-y -y = 360

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The equation y−5=−2(x−3) is in point-slope form. Which shows this equation in slope-intercept form?

MAXImum [283]

y - 5 = -2(x - 3)

Distribute -2.

y - 5 = -2x + 6

Add 5 to both sides.

y = -2x + 11

B) y = -2x + 11

4 0

3 years ago

HELP PLS I HABE BEEN STARING AT THUS QUESTION FOR SO LONG

kari74 [83]

Answer:

56%

Step-by-step explanation:

Reducing the picture by 80% and then by 70% gives a reduction of 56%

70% of 80 = 0.7 × 80 = 56%

7 0

4 years ago

What is the equation of the line that passes through the point (-6,-6) and has a slope of 2/3?

kotegsom [21]

Answer:

-6=2/3*-6

Step-by-step explanation:

y=mx+b

slope = m b=y intercept

6 0

3 years ago

You need 2b cups of flour for making b loaves of bread. You have 8 cups of flour . Do you have enough for 5 loafs of bread?Expla

lubasha [3.4K]

Answer:

No. I don't have enough Flour to make 5 loaves of bread.

From the Amount of flour i had i can make 4 loaves only.

Step-by-step explanation:

Given:

Flour required for making loaves of bread = $2b$ cups

Amount of flour i had = 8 cups

Number of loaves of bread = $b$

We need to find the we have enough flour to make 5 loafs of bread.

Solution:

We know that;

Amount of flour I had is equal to Flour required for making loaves of bread

framing in equation form we get;

$2b=8$

Dividing both side by 2 we get;

$\frac{2b}{2} =\frac{8}{2}$

$b=4$

Hence From the Amount of flour i had i can make 4 loaves only.

Hence I don't have enough Flour to make 5 loaves of bread.

3 0

3 years ago

An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes. The results wer

liraira [26]

Step-by-step explanation:

since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

$\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1$

So probabaility for $\mathrm{X}=1$ is

$P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679$

So expected frequency for $X=1$ is $0.3679^{*} 30=11.037$ (or $\left.11.04\right)$ .

8 0

3 years ago