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3 years ago

7

What is the recursive formula for this geometric sequence? -4,-24,-144,-864,...

1 answer:

balandron [24]3 years ago

7 0

$\bf -4~~,~~\stackrel{-4\cdot 6}{-24}~~,~~\stackrel{-24\cdot 6}{-144}~~,~~\stackrel{-144\cdot 6}{-864}~\hfill \impliedby \begin{array}{llll} \textit{we're multiplying by 6 the previous}\\ \textit{term(n-1) to get the current one} \end{array} \\\\[-0.35em] ~\dotfill\\\\ a_n = a_{n-1}(6)\qquad for~~a_1=-4~~,~~n>2\qquad \impliedby \textit{recursive formula}$

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The CFO of the company believes that an appropriate annual interest rate on this investment is 4%. What is the present value of

hodyreva [135]

Find attached the missing cash flow stream

Answer:

<u><em>Present value = $1,685,334 (rounded to the nearest whole)</em></u>

Explanation:

Since the <em>cash flow stream</em> is <em>uneven</em>, you must discount each stream individually and after you have discounted every stream you can add each preset value to find the net present value.

The formula for <em>present value</em> is:

$\text{Present Value} = \dfrac{\text{Future Value}}{(1+r)^n}\\\\\ Where:\\ \\ r = \text{Rate of return=interest rate}\\ \\ n = \text{Number of periods}$

<u>1. Year 1:</u>

Future value = $250,000
r = 4%
n = 1

$Present\text{ }value=\$250,000/(1+0.04)^1=\$240,384.62$

<u>2. Year 2:</u>

Future value = $20,000
r = 4%
n = 2

$Present\text{ }value=\$20,000/(1+0.04)^2=\$18,491.12$

<u>3. Year 3:</u>

Future value = $330,000
r = 4%
n = 3

$Present\text{ }value=\$330,000/(1+0.04)^3=\$293,368.80$

<u>4. Year 4:</u>

Future value = $450,000
r = 4%
n = 4

$Present\text{ }value=\$450,000/(1+0.04)^4=\$384,661.89$

<u>5. Year 5:</u>

Future value = $550,000
r = 4%
n = 5

$Present\text{ }value=\$550,000/(1+0.04)^5=\$452,059.91$

<u>6. Year 6:</u>

Future value = $375,000
r = 4%
n = 6

$Present\text{ }value=\$375,000/(1+0.04)^6=\$296,367.95$

Total present value = $240,384.62 + $18,491.12 + $293,368.80 + $384,661.89 + $452,059.91 + $296,367.95 + $ 296,367.95

Total present value = $1,685,334.29 = $ 1,685,334

6 0

3 years ago

I need help please!!!!!!!

Sholpan [36]

First box:
(going diagonal from top left to bottom right):

9+0 = 9
0+7 = 7

v

4+4 = 8
4+5 = 9

v

6+3 = 9
3+6 = 9

7 0

3 years ago

Find the equation of the line passing<br> through the points (2, 4) and (3,2).

sineoko [7]

Answer:

y=-2x+8

Step-by-step explanation:

first is to find the slope

m=(y2-y1) /(x2-x1)= (2-4)/(3-2)=-2/1= -2

now using the line formula of y=m*x+b, put in one of the points and solve for b.

2= -2*3 + b

2= -6 + b

8 = b

so y= -2*x+8

3 0

3 years ago

Evaluate. (w^2/x -3) ÷10 × z when w= -4, x = 0.8, and z = -4/5 Enter your answer as a simplified mixed number in the box.

Digiron [165]

Answer:

-1.36

Step-by-step explanation:

(-4^2/0.8-3)/10×-4/5=-1.36

6 0

3 years ago

The population of a community, p(x), is modeled by this exponential function, where x represents the number of years since the p

NeX [460]

An exponential model is used to represent growth of a population

The population after 3 years is 2585

The function is given as:

$\mathbf{P(x) = 2400(1.025)^x}$

<em>3 years after</em>, means that x = 3

So, we have:

$\mathbf{P(3) = 2400(1.025)^3}$

Evaluate exponents

$\mathbf{P(3) = 2400 \times 1.076890625}$

$\mathbf{P(3) = 2584.5375}$

Approximate

$\mathbf{P(3) = 2585}$

Hence, the population after 3 years is 2585

Read more about population growth at:

brainly.com/question/3160736

5 0

3 years ago