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labwork [276]
3 years ago
5

Find the corresponding angles, alternate interior angles, and alternate exterior angles .

Mathematics
1 answer:
yan [13]3 years ago
8 0

Answer:

94

Step By Step Explanation:

6X8=48

5X7=35

1X3=3

2X4=8

48+35+3+8= 94

48+35=83

3+8=11

83+11=94

94

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Look at the picture. What is the solution WORTH 10 POINTS
Ivanshal [37]

The coordinates of the point intersection of lines (-1, -1)

If you want solve:

y = -2x - 3, y = 3x + 2

-2x - 3 = 3x + 2     |+3

-2x = 3x + 5     |-3x

-5x = 5     |:(-5)

x = -1

Put the value of x to the first equation:

y = (-2)(-1) - 3 = 2 - 3 = -1

x = -1, y = -1

3 0
3 years ago
Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
3 years ago
How much interest would be earned on a $3,200 deposit at 3.5% for 1 year?
Fynjy0 [20]

Answer:

Hey there!

I=PRT

I=3200(0.035)(1)

I=112

The interest is 112 dollars.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
Part A: If (7^2)^x = 1, what is the value of x? Explain your answer. (10 points)
Alex777 [14]
Answers:Part A: The value of x is 0.Part B: X can be any real number.
In Part A, you have to first evaluate 7^2. This is 49. Now, write the equation 49^x = 1. We know that if you raise any number to 0, then the answer is 1.
In Part B, you have to first evaluate 7^0, that is 1. Now, we have the equation 1^x = 1. In this case, 1 raised to any exponent is still only 1. Imagine 1^17, this would be 1 times itself 17 times or just 1.
Therefore any number will work in Part B.

3 0
3 years ago
Find the area of an equilateral triangle with side length 9.2 cm. Round your answer to 1 DP.
lbvjy [14]

Answer:

Area=36.66 cm^2

Step-by-step explanation:

First, you need the height.

Use the Pythagorean theorem:

hypotenuse^2=height^2+(1/2 base)^2  

It's one-half base because it's an equilateral triangle.

1/2 base =4.6

(9.2)^2-4.6^2=height^2

84.64-21.16=height^2

height^2=63.48

height=7.97

Area=(1/2)(base)(height)

Area=(1/2)(9.2)(7.97)=36.66 cm^2

3 0
3 years ago
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