Question

Can you help with this?​

Answer 1

Given:

Diagonal of a square = 24 inches

To find:

The perimeter of the given square.

Solution:

Let a be the edge of the square.

Then, the diagonal of the square is

$d=\sqrt{2}a$

Diagonal of a square = 24 inches

$24=\sqrt{2}a$

$\dfrac{24}{\sqrt{2}}=a$

$\dfrac{24}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}=a$

$\dfrac{24\sqrt{2}}{2}=a$

$12\sqrt{2}=a$

The perimeter of the square.

$Perimeter=4a$

$Perimeter=4(12\sqrt{2})$

$Perimeter=48\sqrt{2}$

Therefore, the perimeter of the square is $48\sqrt{2}$.