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Nitella [24]
3 years ago
15

A pack of 8 batteries cost 4.99

Mathematics
1 answer:
Yuliya22 [10]3 years ago
5 0
1.6 is the answer the nearest penny would be 2

Just divide 8 by 4.99
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Make x the subject. help please
valkas [14]

Answer:

\sf x = \dfrac{n - 2mp}{2m}

Step-by-step explanation:

              \sf 3m = m + \dfrac{n}{p + x}\\

        \sf 3m - m = \dfrac{n}{p +x}

                \sf 2m = \dfrac{n}{p +x}

Now cross multiply,

          2m*(p +x) = n

To open the parenthesis, multiply 2m by p and x.

        2mp + 2mx = n

 Isolate the term with variable 'x'

                    2mx = n - 2mp

Now, isolate 'x', by dividing both sides by 2m

                          \sf  x = \dfrac{n-2mp}{2m}                            

4 0
2 years ago
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7. A dress that normally sells for $72 is on sale for $45. What is the percent decrease in the price? ​
ozzi

Actual price of the dress = 72

Selling price = 45

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Percentage of decrease =

\frac{27}{72}  \times 100 \\

<h3>= <u>37.5%</u></h3>

.... Hope this will help.....

5 0
3 years ago
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The perimeter of the original rectangle on the left is 30 meters. The perimeter of the reduced rectangle on the right is 24 mete
OlgaM077 [116]

Answer:

5 meters

Step-by-step explanation:

If the smallest rectangle has a length of 8 meters, and a perimeter of 24 meters then its width is given by:

24 = 2*8+2*W_1\\W_1= 4\ meters

We can conclude that the width is half of the length for both rectangles. Therefore, the width of the larger rectangle, with a perimeter of 30 meters, is:

30 = 2*W_2+2*L_2\\30 = 2*W_2+4*W_2\\W_2=5\ meters

The width of the original rectangle is 5 meters.

6 0
3 years ago
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fenix001 [56]

Step-by-step explanation:

Area of shaded region = area of exterior rectangle - area of interior rectangle

37 \times 28 - 11 \times 20 \\  \\  = 1,036 - 220 \\  \\  = 816 \:  {yards}^{2}  \\

4 0
3 years ago
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Which is Bigger y=6x+4, or y=3(x)+ 2
antoniya [11.8K]
Y=6x is bigger because they have the same variables, but the known numbers in the first equation are doubled
5 0
3 years ago
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